Which equation shows the point-slope form of the line that passes through (3, 2) and has a slope of 1/2

An equivalent expression with a rational denominator is...

Whitepunk [10]

Given the expression,

$(8x-56x^2)/(\sqrt{14x-2})$

We will have to rationalize the denominator first. To rationalize the denominator we have to multiply the numerator and denominator both by the square root part of the denominator.

$[(8x-56x^2)(\sqrt{14x-2})]/[(\sqrt{14x-2})(\sqrt{14x-2})]$

If we have $(\sqrt{a})(\sqrt{a})$ , we will get $\sqrt{a^2}$ by multiplying them. And $\sqrt{a^2} = a$ .

So here in the problem, we will get,

$[(8x-56x^2)(\sqrt{14x-2})]/(14x-2)$

Now in the numerator we have $(8x-56x^2)$ . We can check 8x is common there. we will take out -8x from it, we will get,

$-8x(-1+7x)$

$-8x(7x-1)$

And in the denominator we have $14x-2$ . We can check 2 is common there. If we take out 2 from it we will get,

$2(7x-1)$

So we can write the expression as

$[(-8x)(7x-1)(\sqrt{14x-2})]/[2(7x-1)]$

$(7x-1)$ is common to the numerator and denominator both, if we cancel it we will get,

$(-8x)(\sqrt{14x-2})/2$

We can divide -8 by the denominator, as -8 os divisible by 2. By dividing them we will get,

$(-4x)(\sqrt{14x-2})$

$(-4x)(14x-2)^(1/2)$

So we have got the required answer here.

The correct option is the last one.

4 0

3 years ago

2. Sammie has 3 feet of ribbon. She is making bows for her friends that each use of 1/3 of a foot

lilavasa [31]

Answer:

Sammy can make 9 bows.

Step-by-step explanation:

3 feet of Ribbon

1/3 for each bow

1/3 + 1/3 +1/3 = 3/3 or 1 so she can make 3 bows out of one foot of ribbon

so if you repeat this than you should get 9 bows out of three feet of ribbion.

3 0

3 years ago

For what values of <img src="https://tex.z-dn.net/?f=x" id="TexFormula1" title="x" alt="x" align="absmiddle" class="latex-formul

11Alexandr11 [23.1K]

Answer:

$x1$

Step-by-step explanation:

We have:

$(x+5)(x-1)$

And we want to find the value of x such that the expression is positive. So, we can write this as the following inequality:

$(x+5)(x-1)>0$

Solve for the inequality. First, we can solve for the zeros like a normal quadratic. So, pretend the inequality is with an equal sign:

$(x+5)(x-1)=0$

Zero Product Property:

$x+5=0\text{ or } x-1=0$

On the left, subtract 5.

On the right, add 1.

So, our zeros are:

$x=-5, 1$

Since our inequality is a greater than, our answer is an "or" inequality with our answer being all the values to the left of our lesser zero and all the values to the right of our greater zero.

So, our solution is:

$x1$

And we're done!

7 0

3 years ago

Read 2 more answers

Gcf of 63 and 27 i will give toy 12pts

NeTakaya

GCF is 3×3 so it is 9

4 0

3 years ago

I Need The Answer Plz Geometry Is Hard!!

otez555 [7]

Answer:

14

Step-by-step explanation:

In a triangle, the midline joining the midpoints of two sides is parallel to the third side and half as long, so

FB = EC/2

2x - 6 = 44/2

2x - 6 = 22

2x = 22 + 6

2x = 28

x = 28/2

x = 14

6 0

3 years ago