Just do L×W×H hope this helps
Answer:
Mean: 40.17 years.
Standard deviation: 10.97 years.
Step-by-step explanation:
The frequency distribution is in the attached image.
We can calculate the mean adding the multiplication of midpoints of each class and frequency, and dividing by the sample size.
The midpoints of a class is calculated as the average of the bounds of the class.
Then, the mean can be written as:
The standard deviation can be calculated as:
![s=\sqrt{\dfrac{1}{N-1}\sum f_i(X_i-E(X))^2}\\\\\\s=\sqrt{\dfrac{1}{59}[3(15-40.17)^2+7(25-40.17)^2+18(35-40.17)^2+20(45-40.17)^2+12(55-40.17)^2]}](https://tex.z-dn.net/?f=s%3D%5Csqrt%7B%5Cdfrac%7B1%7D%7BN-1%7D%5Csum%20f_i%28X_i-E%28X%29%29%5E2%7D%5C%5C%5C%5C%5C%5Cs%3D%5Csqrt%7B%5Cdfrac%7B1%7D%7B59%7D%5B3%2815-40.17%29%5E2%2B7%2825-40.17%29%5E2%2B18%2835-40.17%29%5E2%2B20%2845-40.17%29%5E2%2B12%2855-40.17%29%5E2%5D%7D)
Answer:
Lol, okay Bob will get $42,069 if he posts all his memes! Man, where can I get a job like that?!
14,023 x 3 = 42,069
Answer:
Jake is 9, and Jake's dad is 43.
Step-by-step explanation:
Ok, let's start off by putting a variable for Jack's age, A.
We know that Jack's father is 2 less than 5 times, so we can write his as 5x -2.
Now let's make an equation:
52 = x + 5x - 2
We need to isolate the x-values so we need to add 2 on both sides:
54= x + 5x
No we need to add the like terms:
54 = 6x
Finally, we just divide by 6 on each side.
Now we know X = 9 but we're not done yet :)
So because Jake's dad is almost 5 times as much, we first multiply Jack's age by 5. We get 45 but we need to subtract 2 which leaves us with 43.
Answer:
Domain : { -3, 0, 3}
Range : { 1 , 1 , 1 }
Function : These set of ordered pairs are functions as every x-value has only one y-value associated with it.
