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LuckyWell [14K]
2 years ago
12

Bob ate 12 cookies over the past two days. Assume he ate the same amount of cookies each day. How many cookies did Jonathan eat

per day?
Mathematics
2 answers:
docker41 [41]2 years ago
7 0

Answer:

Its 6 cookies per day

Step-by-step explanation:

12/2=6 6 cookies per day

lozanna [386]2 years ago
5 0
12 cookies within 2 days..
12/6=2

However, Bob-Jonathan?
This is a confusing question because jonathan is not mentioned..

I hope this helps! Let me know if you have any questions! Good luck on the rest of your assessment!

Mark this as Brainliest if you get a chance:)
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The cube less the square of a number is twice the number. If x is a positive integer, what is its value
olga55 [171]

Answer:

2

Step-by-step explanation:

let 'x' = number

x³ - x² = 2x

x³- x² - 2x = 0

x(x² - x - 2) = 0

x(x - 2)(x + 1) = 0

x = -1, 0, 2

the only positive solution is the number 2

3 0
2 years ago
Lindy puts £ 78 into an account which pays inrerest at a rate of 5% per anum. What will be the simple interest after 6 years .wh
Alika [10]

Answer:

Interest: £23.4

Amount: £101.4

Step-by-step explanation:

6 × 5/100 × 78 = 23.4

Balance: 78 + 23.4 = 101.4

5 0
2 years ago
Read 2 more answers
!!!!1SUPER EASYY!! NO PAPER NEEDED !! WILL GIVE BRAINLY!!
lions [1.4K]
I believe it is -8y + 5x - 3
6 0
2 years ago
Determine the least common multiple (LCM) of 48 and 16.<br>A. 16<br>B. 24<br>C. 36<br>D. 48​
Marizza181 [45]

Answer:

16

since it's the least that can be divided by both

7 0
2 years ago
Read 2 more answers
Rewrite as a simplified fraction. 2. 14 ‾ = ?
SOVA2 [1]

Answer:

1/7

Step-by-step explanation:

- I can't really tell what the fraction you have is, I am assuming it is 2/14. If that is correct, simplify by finding a common number.

- Ask yourself, what can both be divided by? (Answer is 2)

- Knowing both simplify by 2, divide the numerator (top) and denominator (bottom) by 2.

- You should get 1/7 (2/2 = 1 and 14/2 = 7)

- If you have any further questions on this topic please let me know. I would be glad to help anytime!

6 0
3 years ago
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