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3 years ago

8/2(2+2) Hurry Read comment

Mathematics

1 answer:

Sveta_85 [38]3 years ago

7 0

My answer is 16.

Have a good night

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You might be interested in

What kind of triangle does it form?

Gwar [14]

Answer:

It forms a scalene triangle

Step-by-step explanation:

This is because scalene triangle does not have any of its sides equal.

$\sqrt{111}$ is also 10.54.And looking at the measurements none of it are equal to each other so therefore it is a scalene triangle

7 0

3 years ago

Can 0.999.... be 1

riadik2000 [5.3K]

0.999999999... indeed can be 1.
Same as 0.33333... is equal to 1/3. Though you can see it's a fraction.
Same thing is basically with 0.99999... to 1. It's just the fact that the 1 is a whole number but the 0.9999... looks messy.
The terms of the associated sequence 0.9, 0.99, 0.999,..., do "get arbitrarily close" to 1, in the sense that, for each term in the progression, the difference between the term and 1 gets smaller and smaller.
The number 0.999... (with the ellipse) means that it goes on forever, there is no stop to it meaning that it basically is, and has been proven, that it is 1.

Hope this helps :)

8 0

3 years ago

Read 2 more answers

Assume the following: 1) the scattergraph intersects the Y axis at $200; 2) the estimated line on the scattergraph increases by

Schach [20]

Answer:

The total cost is:$400

Step-by-step explanation:

Given

$x \to units$

$y \to cost$

$(x,y) = (0,200)$ --- when the graph intersects the y-axis

$m = 10$ -- the rate

Required

y when x = 20

First, we determine the equation of the plot using:

$y = mx + c$

Substitute 10 for m

$y = 10x + c$

Next, solve for c.

Substitute $(x,y) = (0,200)$

$200 = 10*0+c$

$200 = 0+c$

$c = 200$

So:

$y = 10x + c$

$y =10x + 200$

When x = 20

$y =10*20 + 200$

$y =200 + 200$

$y = 400$

7 0

3 years ago

We want to factor the following expression: 25x^2−36y^8 We can factor the expression as (U+V)(U-V) where U and V are either cons

Aneli [31]

Answer:

$U=5\,x$

$V=6\,y^4$

Step-by-step explanation:

Recall that an expression that can be factored as (U+V)(U-V) using distributive property for multiplication of binomials, should render: $U^2-V^2$ (the factorization given above is that of a difference of squares. Then, the idea is to write the original expression :

$25\,x^2-36\,y^8$

as a difference of perfect squares. Let's examine each term and its numerical and variable form to find if they can be written as perfect squares:

a) the term $25\,x^2=5^2\,x^2=(5x)^2$ therefore, if we assign the letter U to $5\,x$ , the first term becomes:

$25\,x^2=(5\,x)^2=U^2$

b) the term $-36\,y^8=-6^2\,(y^4)^2=-(6\,y^4)^2$ therefore, if we assign the letter V to $6\,y^4$ , this second term becomes:

$-36\,y^8=-(6\,y^4)^2=-V^2$

With the above identification, our expression can now be factored as a difference of squares:

$25\,x^2-36\,y^8=(5\,x)^2-(6\,y^4)^2=U^2-V^2=(U+V)(U-V)$

5 0

3 years ago

2 questions ples answer

OverLord2011 [107]

1. We are given:
$a^2 = 64$

The only a which squared gives you 64 is 8. The perimeter of an 8 by 8 square will be 32. Half of that is 16. Now, let's see what we can do. We can set up:
$4a = 16$

Obviously, each side length has to be 4. So, the area of this square will be 16 units².

2. Let n equal her son's age. So, her age right now will be (S = her age):
$S = 18n$
1 year ago it was:
$S-1 = 3n$

We have 2 equations, let's substitute. We can rewrite this as:
$18n-1 = 3n$
Solve for n:
$15n-1=0$
$n= \frac{1}{15}$

We know the value of n, which is her son's age. So, her son is 1/15 of a year old or about 24 days old.

8 0

4 years ago