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3 years ago

! PLEASE HELP !

Mathematics

2 answers:

trasher [3.6K]3 years ago

8 0

Answer:

0.2 with a line on top of the 2

Step-by-step explanation:

It's a repeating decimal. It will always go with a 2

Dennis_Churaev [7]3 years ago

6 0

Answer:

0.2222

Step-by-step explanation:

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Please bros, I need this.

bija089 [108]

A is a compound event
b is a compound event
c is not a compound event since the coin only has 2 possibilities, if the coin is a dice or if it was removed it would be compound

4 0

3 years ago

Lim n-> infinity [1/3 + 1/3² + 1/3³ + . . . .+ 1/3ⁿ]

Verizon [17]

Answer:

$\large\underline{\sf{Solution-}}$

Given expression is

$\rm :\longmapsto\:\displaystyle\lim_{n \to \infty }\rm \bigg[\dfrac{1}{3} + \dfrac{1}{ {3}^{2} } + \dfrac{1}{ {3}^{3} } + - - + \dfrac{1}{ {3}^{n} } \bigg]$

Let we first evaluate

$\rm :\longmapsto\:\dfrac{1}{3} + \dfrac{1}{ {3}^{2} } + \dfrac{1}{ {3}^{3} } + - - + \dfrac{1}{ {3}^{n} }$

Its a Geometric progression with

$\rm :\longmapsto\:a = \dfrac{1}{3}$

$\rm :\longmapsto\:r = \dfrac{1}{3}$

$\rm :\longmapsto\:n = n$

So, Sum of n terms of GP series is

$\rm :\longmapsto\:S_n = \dfrac{a(1 - {r}^{n} )}{1 - r}$

$\rm :\longmapsto\:S_n = \dfrac{1}{3} \bigg[\dfrac{1 - {\bigg[\dfrac{1}{3} \bigg]}^{n} }{1 - \dfrac{1}{3} } \bigg]$

$\rm :\longmapsto\:S_n = \dfrac{1}{3} \bigg[\dfrac{1 - {\bigg[\dfrac{1}{3} \bigg]}^{n} }{\dfrac{3 - 1}{3} } \bigg]$

$\rm :\longmapsto\:S_n = \dfrac{1}{3} \bigg[\dfrac{1 - {\bigg[\dfrac{1}{3} \bigg]}^{n} }{\dfrac{2}{3} } \bigg]$

$\bf\implies \:S_n = \dfrac{1}{2}\bigg[1 - \dfrac{1}{ {3}^{n} } \bigg]$

Hence, 

$\bf :\longmapsto\:\dfrac{1}{3} + \dfrac{1}{ {3}^{2} } + \dfrac{1}{ {3}^{3} } + - - + \dfrac{1}{ {3}^{n} } = \dfrac{1}{2}\bigg[1 - \dfrac{1}{ {3}^{n} } \bigg]$

Therefore, 

$\purple{\rm :\longmapsto\:\displaystyle\lim_{n \to \infty }\rm \bigg[\dfrac{1}{3} + \dfrac{1}{ {3}^{2} } + \dfrac{1}{ {3}^{3} } + - - + \dfrac{1}{ {3}^{n} } \bigg]}$

$\rm \: = \: \displaystyle\lim_{n \to \infty }\rm \dfrac{1}{2}\bigg[1 - \dfrac{1}{ {3}^{n} } \bigg]$

$\rm \: = \: \rm \dfrac{1}{2}\bigg[1 - 0 \bigg]$

$\rm \: = \: \rm \dfrac{1}{2}$

Hence, 

$\purple{\rm :\longmapsto\:\boxed{\tt{ \displaystyle\lim_{n \to \infty }\rm \bigg[\dfrac{1}{3} + \dfrac{1}{ {3}^{2} } + \dfrac{1}{ {3}^{3} } + - - + \dfrac{1}{ {3}^{n} } \bigg]} = \frac{1}{2}}}$

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<h3>Explore More</h3>

$\rm :\longmapsto\:\boxed{\tt{ \displaystyle\lim_{x \to 0}\rm \frac{sinx}{x} = 1}}$

$\rm :\longmapsto\:\boxed{\tt{ \displaystyle\lim_{x \to 0}\rm \frac{tanx}{x} = 1}}$

$\rm :\longmapsto\:\boxed{\tt{ \displaystyle\lim_{x \to 0}\rm \frac{log(1 + x)}{x} = 1}}$

$\rm :\longmapsto\:\boxed{\tt{ \displaystyle\lim_{x \to 0}\rm \frac{ {e}^{x} - 1}{x} = 1}}$

$\rm :\longmapsto\:\boxed{\tt{ \displaystyle\lim_{x \to 0}\rm \frac{ {a}^{x} - 1}{x} = loga}}$

8 0

3 years ago

Find the value of x pls help

Ierofanga [76]

The answer is 20 because yo just set them equal to each other

6 0

3 years ago

PLEASE HELP, ILL DO ANYTHING!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

SSSSS [86.1K]

The dimensions of the original picture are 12 by 18. Adding the mat of width x around the picture makes the new dimensions of the whole thing (18+2x)(12+2x). Now we need to find x, the width of the mat, in order to then find the new dimensions. We want the largest frame, so we will assume all 80 inches of wood are used.

To find x, notice that the total area - the original picture area = the area of just the wood used. This must equal 80. So let's set up an equation and solve for x.

(18 + 2x) (12 + 2x) - 18 * 12 = 80
216 + 36x + 24x + 4x^2 - 216 = 80
4x^2 + 60x = 80
4x^2 + 60x - 80 = 0

Divide by GCF, which is 4, to simplify the equation: x^2 + 15x - 20 = 0 Now this can't be factored, so you must either use the quadratic formula or plug it into your graphing calculator and find the x-intercepts. EIther way the zeros are x = 1.2321, and x = -16.2337 But this is a word problem so we can't have a negative length for x. So the only valid solution for x is 1.2321. This is the width of the mat all around the 12 * 18 picture.

Now let's use x to find the new dimensions: Remember that the new dimensions are formed by adding 2x (that is, 2 times x, with x being the width of the mat) to the length and width of the original picture. New width with mat = 12 + 2x = 12 + 2*1.2321 = 14.46 in New length with mat = 18 + 2x = 18 + 2.1.2321 = 20.46 in

4 0

4 years ago

Ethanhunt help please :D:D:D:D

kirill115 [55]

A) In 1st Figure, Blue boxes means unit of diet soda = 8
Green boxed is regular sods = 4

Total Boxes = 12
Value of 1 Box = 888/12 = 74

Now, We know, we have 74 soda in each box, and 8 boxes of diet soda, so the number of diet soda = 74 * 8 = 592

In short, Your Answer would be: 592

B.) Now, In 2nd figure, You can see
Red boxes mean Short sleeve short which is = 3
Green means Long sleeve = 7

Total Boxes = 10
Value of 1 Box = 460/10 = 46

Now, we know we have 46 shirts in each boxes and their is 3 boxes of short sleeves.
So, Number of Short sleeves = 46 * 3 = 138

In short, Your Answer would be: 138

Hope this helps!

6 0

4 years ago

Read 2 more answers