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3 years ago

Find the equation of the line parallel to y=5x+7 and passing through (3,-8)

Mathematics

1 answer:

skelet666 [1.2K]3 years ago

6 0

Answer:

hope it helps you thank you

Step-by-step explanation:

mark me as brilliant

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6 3/4 % 5 1/2<br><br> This % means divided by

yuradex [85]

Divided by the 5 1/2

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3 years ago

Factor completely x^2-12x+36

Elenna [48]

Answer:

${(x - 6)}^{2}$

Step-by-step explanation:

$= {x}^{2} - 12x + 36 \\ = {x}^{2} - (6 + 6)x + 36 \\ = {x }^{2} - 6x - 6x + 36 \\ = x(x - 6) - 6(x - 6) \\ =(x - 6)(x - 6) \\ = {(x - 6)}^{2}$

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3 years ago

The product of 7 and the sum of a number and -6

Hoochie [10]

This is middle school work woah

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3 years ago

F(x)=x^3+10x^2+31x+30

Colt1911 [192]

The factors of the given polynomial will be ( x + 2 ), ( x + 5 ) and ( x + 3 ).

<h3>What is an expression?</h3>

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication and division.

The given expression will be solved as:-

f(x) = x³ + 10x² + 31x + 30

f(x) = ( x³ + 7x² + 10x + 3x² + 21x + 30

f(x) = ( x² + 7x + 10 ) ( (x + 3 )

f(x) = ( x²+ 5x + 2x + 10 ) ( x + 3 )

f(x) =[ x ( x+ 5 ) +2 ( x+ 5) ] ( x + 3 )

f(x) = ( x + 5 ) ( x + 2 ) ( x + 3 )

Therefore factors of the given polynomial will be ( x + 2 ), ( x + 5 ) and ( x + 3 ).

To know more about Expression follow

brainly.com/question/723406

#SPJ1

5 0

2 years ago

Find the components of the vertical force Bold Upper Fequalsleft angle 0 comma negative 8 right anglein the directions parallel

nydimaria [60]

Answer with Step-by-step explanation:

We are given that

F=<0,-8>=0i-8j=-8j

$\theta=\frac{\pi}{3}$

The component of force is divided into two direction

1.Along the plane

2.Perpendicular to the plane

1.The vector parallel to the plane will be= $r=cos\frac{\pi}{3}i-sin\frac{\pi}{3}j=\frac{1}{2}i-\frac{\sqrt 3}{2}j$

By using $cos\frac{\pi}{3}=\frac{1}{2},sin\frac{\pi}{3}=\frac{\sqrt 3}{2}$

Force along the plane will be= $\mid F_x\mid=F\cdot r$

Force along the plane will be = $\mid F_x\mid=F\cdot (\frac{1}{2}i-\frac{\sqrt 3}{2}j)=-8j\cdot(\frac{1}{2}i-\frac{\sqrt 3}{2}j)=8\times \frac{\sqrt 3}{2}=4\sqrt 3$ N

By using $i\cdot i=j\cdoty j=k\cdot k=1,i\cdot j=j\cdot k=k\cdot i=j\cdot i=k\cdot j=i\cdot k=0$

Therefore, force along the plane= $\mid F_x\mid(\frac{1}{2}i-\frac{\sqrt 3}{2}j)=4\sqrt 3(\frac{1}{2}i-\frac{\sqrt 3}{2}j)$

2.The vector perpendicular to the plane= $r=-sin\frac{\pi}{3}-cos\frac{\pi}{3}=-\frac{\sqrt 3}{2}i-\frac{1}{2}j$

The force perpendicular to the plane= $\mid F_y\mid=F\cdot r=-8j(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)$

The force perpendicular to the plane= $4$ N

Therefore, $F_y=4(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)$

Sum of two component of force= $F_x+F_y=4\sqrt 3(\frac{1}{2}i-\frac{\sqrt 3}{2}j)+4(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)$

Sum of two component of force= $2\sqrt 3i-6j-2\sqrt3 i-2j=-8j$

Hence,sum of two component of forces=Total force.

6 0

3 years ago