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trapecia [35]
3 years ago
14

Which situation can be represented by the equation 4x=32

Mathematics
1 answer:
mr_godi [17]3 years ago
4 0

Answer:

8

Step-by-step explanation:

4x=32

÷4 ÷4

__________

x=8

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The area of a triangular flag is 132 square centimetres. Its altitude is 2 centimetres longer than twice its base. Find the leng
Anika [276]

Answer:

24 cm and 11 cm

Step-by-step explanation:

GIVEN: The area of a triangular flag is 132 \text{ cm}^2. Its altitude is 2\text{ cm} longer than twice its base.

TO FIND: lengths of the altitude and the base.

SOLUTION:

Let the altitude and the base of flag be a and b

According to the question

a=2+2b

area of triangle =\frac{1}{2}\times base \times alltitude=\frac{1}{2}a\times b

\implies \frac{1}{2}(2b+2)b=132 \Rightarrow 2b^2+2b-264

Solving equation we get

b=11   then a=24

Hence the lengths of altitude and base of triangular flag is 24 cm and 11 cm respectively.

8 0
3 years ago
What is 20 less than 1000​
Phoenix [80]

20 less than 1000 is the same thing as 1000 minus 20.

1000 minus 20 is 980.

20 less than 1000 is 980.

6 0
3 years ago
Read 2 more answers
Please answer me write a statement that why isnt 6.5 / 0.5 = 3.25
REY [17]

Answer:

13

Step-by-step explanation:

It's not 3.25 because if you simplify 6.5 and 0.5, you get 65 and 5 which if you divide is 13.

4 0
3 years ago
List all subsets of ta, b, c, d, e) containing a but not containing b
fomenos

Answer:

(a), (a,c), (a,d), (a,e), (a,c,d), (a,c,e), (a,d,e), (a,c,d,e)

Step-by-step explanation:

We are given the set (a,b,c,d,e).

Total number of subsets of the above set are 2^5 = 32

Subsets:

φ

(a,b,c,d,e)

(a), (b), (c), (d), (e)

(a,b), (a,c), (a,d), (a,e), (b,c), (b,d), (b,e), (c,d), (c,e), (d,e)

(a,b,c), (a,b,d), (a,b,e), (a,c,d), (a,c,e), (a,d,e), ( b,c,d), (b,c,e), (b,d,e), (c,d,e)

(a,b,c,d), (a,b,c,e), (a,b,d,e), (a,c,d,e), (b,c,d,e)

Subset having a but not b :

(a), (a,c), (a,d), (a,e), (a,c,d), (a,c,e), (a,d,e), (a,c,d,e)

7 0
4 years ago
A ball moves in a straight line has an acceleration of a(t) = 2t + 5. Find the position function of the ball if its initial velo
Vlad1618 [11]

Answer:

s(t) = frac{t^3}{3} + \frac{5t^2}{2} - 3t + 12

Step-by-step explanation:

Relation between acceleration, velocity and position:

The velocity function is the integral of the acceleration function.

The position function is the integral of the velocity function.

Acceleration:

As given by the problem, the acceleration function is a(t) = 2t + 5

Velocity:

v(t) = \int a(t) dt = \int (2t+5) dt = \frac{2t^2}{2} + 5t + K = t^2 + 5t + K

In which K is the constant of integration, which is the initial velocity. So K = -3 and:

v(t) = t^2 + 5t - 3

Position:

s(t) = \int v(t) dt = \int (t^2 + 5t - 3) = \frac{t^3}{3} + \frac{5t^2}{2} - 3t + K

In which K, the constant of integration, is the initial position. Since it is 12:

s(t) = frac{t^3}{3} + \frac{5t^2}{2} - 3t + 12

4 0
3 years ago
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