Answer:
THE THIRD ONE
Step-by-step explanation:
Radius =
9^2 + 9^2 = d^2
d = sqrt(162), about 12.73
theta =
atan(9/-9)
is 45°, but in 2nd quad, so add 90
(12.727, 135°)
Answer:
2 real solutions
Step-by-step explanation:
We can use the determinant, which says that for a quadratic of the form ax² + bx + c, we can determine what kind of solutions it has by looking at the determinant of the form:
b² - 4ac
If b² - 4ac > 0, then there are 2 real solutions. If b² - 4ac = 0, then there is 1 real solution. If b² - 4ac < 0, then there are 2 imaginary solutions.
Here, a = 6, b = -20, and c = 1. So, plug these into the determinant formula:
b² - 4ac
(-20)² - 4 * 6 * 1 = 400 - 24 = 376
Since 376 is clearly greater than 0, we know this quadratic has 2 real solutions.
<em>~ an aesthetics lover</em>
Answer:
1 and 2 are rectagles and 3 is not
Step-by-step explanation:
Answer:
B, the second one down on the first page
Step-by-step explanation:
hope this helps! :D
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