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3 years ago

Show by dimension that the equation of motion is correct V² = U²+2as

Physics

1 answer:

borishaifa [10]3 years ago

5 0

Answer:

i think its 56as

Explanation:

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Equations of the vertical launch:

Vf = Vo - gt

y = yo + Vo*t - gt^2 / 2

Here yo = 35.0m
Vo is unknown
y final = 0
t = 4.00 s
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2 years ago

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Answer:

Explanation:

Given height of lamp from the ceiling = 2.6m

mass of the lamp = 3.8kg

acceleration due to gravity = 9.81m/s²

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Gravitational potential energy = mass*acc due to gravity * height

Gravitational potential energy = 3.8*2.6*9.81

Gravitational potential energy = 96.923 Joules

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m = mass of the body (in kg)

v = velocity of the body (in m/s²)

To get the velocity v, we will use the equation of motion $v^{2} = u^{2}+2gh$

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Since mass = 3.8kg

$K.E = 1/2 * 3.8 *7.14^{2}\\ K.E = 96.86Joules$

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Show by dimension that the equation of motion is correct V² = U²+2as​

Show by dimension that the equation of motion is correct V² = U²+2as