You place a +1.00 mC charged object in an electric field of 900 N/C that points due East. Determine the magnitude and direction
1 answer:
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Answer:
F = 4000 N
Explanation:
given,
mass of rocket (M)= 5000 Kg
10 Kg gas burns at speed (m)= 4000 m/s
time = 10 s
average force = ?
at the end the rocket is at rest
by conservation of momentum
M v + m v' = 0
5000 x v - 10 x 4000 = 0
5000 v = 40000
v = 8 m/s
speed of rocket = 8 m/s
now,
we know
change in momentum = F x Δ t
F = 4000 N
Hence, the average force applied to the rocket is equal to F = 4000 N
Answer:
Explanation:
Given that,
The mass of a golf ball, m = 40 g = 0.04 kg
Its angular velocity,
The radius of the sphere is 2.5 cm or 0.025 m
We need to find the magnitude of the angular momentum of the ball. It is given by the formula as follows:
Where I is moment of inertia
For sphere,
So, the magnitude of the angular momentum of the sphere is .