<span>83.9%
First, determine the molar masses of Al(C6H5)3 and C6H6. Start by looking up the atomic weights of the involved elements.
Atomic weight aluminum = 26.981539
Atomic weight carbon = 12.0107
Atomic weight hydrogen = 1.00794
Molar mass Al(C6H5)3 = 26.981539 + 18 * 12.0107 + 15 * 1.00794 = 258.293239 g/mol
Molar mass C6H6 = 6 * 12.0107 + 6 * 1.00794 = 78.11184 g/mol
Now determine how many moles of C6H6 was produced
Moles C6H6 = 0.951 g / 78.11184 g/mol = 0.012174851 mol
Looking at the balanced equation, it indicates that 1 mole of Al(C6H5)3 is required for every 3 moles of C6H6 produced. So given the number of moles of C6H6 you have, determine the number of moles of Al(C6H5)3 that was required.
0.012174851 mol / 3 = 0.004058284 mol
Then multiply by the molar mass to get the number of grams that was originally present.
0.004058284 mol * 258.293239 g/mol = 1.048227218 g
Finally, the weight percent is simply the mass of the reactant divided by the total mass of the sample. So
1.048227218 g / 1.25 g = 0.838581775 = 83.8581775%
And of course, round to 3 significant digits, giving 83.9%</span>
Moles H2O = 1233 g/ 18 g/mol=68.5 68.5 x 40.7 =2788 kJ
The volume of the gas mixture is 1.7 L and its total pressure is 0.810 atm. ... If the carbon and oxygen react completely to form CO(g), what will be the final .... acid to generate hydrogen gas, which is collected over a liquid whose vapor ..... It takes more energy to add an electron to fluorine than to oxygen because the radius
Answer:
Both animal and plant cells are eukaryotic cells and have several similarities. The similarities include common organelles like cell membrane, cell nucleus, mitochondria, endoplasmic reticulum, ribosomes and golgi apparatus
Explanation:
hey both contain membrane-bound organelles such as the nucleus, mitochondria, endoplasmic reticulum, golgi apparatus, lysosomes, and peroxisomes.
