Na2C03 is formed through the reaction of
NaOH and H2CO3 namely sodium hydroxide and carbonic acid
NaOH -> strong base
H2CO3-> weak acid
The mass of nitrogen gas that participated in the chemical reaction is 1.54g
HOW TO CALCULATE MASS OF AN ELEMENT:
- Mass of a substance can be calculated by multiplying the number of moles in mol of the substance by its molecular mass in g/mol. That is;
- mass (M) = molar mass (MM) × number of moles (n)
According to this question, a chemist determines by measurements that 0.0550 moles of nitrogen gas (N2) participate in a chemical reaction.
- The molecular mass of nitrogen gas (N2) = 14.01(2)
= 28.02g/mol
Hence, the mass of the nitrogen gas that participated in the chemical reaction is calculated as follows:
- Mass (g) = 0.0550 mol × 28.02 g/mol
Therefore, the mass of nitrogen gas that participated in the chemical reaction is 1.54g
Learn more: brainly.com/question/18269198
Answer:
Don't know if I know itat all
Explanation:
what is red data list
Sulfur has 6 electrons, so we put 6 in the first spot.
Oxygen has 6 electrons too, but since there are 3, we would multiply 6 times 3 , which equals 18, then add that too.
The 2 is added because there is that negative 2 at the top of the formular, which indicates the presence of two extra valence electrons.
the equation would be
6 + 18 + 2 = 26
