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ehidna [41]
3 years ago
10

2.

Chemistry
1 answer:
Anna007 [38]3 years ago
4 0

Answer:

A is the answer..............

.............

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What element contains 25 protons?
kolezko [41]

Answer:

Manganese since 25 protons is 25 atomic number

Explanation:

5 0
3 years ago
Read 2 more answers
A mole of X reacts at a constant pressure of 43.0 atm via the reaction X(g)+4Y(g)→2Z(g), ΔH∘=−75.0 kJ Before the reaction, the v
hoa [83]

Answer:

The total energy change, ΔE, in kilojoules = -61.93 kJ

Explanation:

Relationship between ΔH, ΔE and work done is given by first law of thermodynamics.

ΔE = ΔH - PΔV

Where,

ΔH = Change in enthalpy

ΔE = Change in internal energy

PΔV = Work done

Given that,

ΔH = -75.0 kJ = -75000 J

P = 43.0 atm

ΔV = Final volume - initial volume

    = (2.00 - 5.00) = -3.00 L

PΔV = 43 × (-3.00) = -129 L atm

1 L atm = 101.325 J

-129 L atm = 129 × 101.325 = -13071 J

So ,

ΔE = ΔH - PΔV

     = (-75000 J) - ( -13071 J)

     =  -75000 J + 13071 J

     = -61929 J

Total energy change, ΔE = -61.929 kJ

3 0
4 years ago
What kind of data would you need to collect to carry out this experiment?
JulijaS [17]
You need to specify the experiment to get an answer.  However, most experiments require qualitative data (descriptive, non-numerical data) and quantitative data (measured, numerical data).
4 0
4 years ago
Container A (with volume 1.23 L) contains a gas under 3.24 atm of pressure. Container B (with volume
kolbaska11 [484]

Now that a lot of pressure

8 0
3 years ago
Consider the following intermediate chemical equations.
mixas84 [53]

Answer:

CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(l).

Explanation:

  • We have two equations:

CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(g)

2H₂O(g) → 2H₂O(l)

  • To add the two equations: we omit H₂O(g)  that is formed by 2 moles in the product side of the first equation and consumed by 2 moles from the reactants side in the second equation

  • So, the overall chemical equation is obtained by combining these intermediate equations is:

<em>CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(l).</em>

<em></em>

8 0
3 years ago
Read 2 more answers
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