Answer:
16.2 s
Explanation:
Given:
Δx = 525 m
v₀ = 0 m/s
a = 4.00 m/s²
Find: t
Δx = v₀ t + ½ at²
525 m = (0 m/s) t + ½ (4.00 m/s²) t²
t = 16.2 s
Answer:
8.1345°
Explanation:
We apply
to the wire to obtain:

#The magnitude of the magnetic force acting on the wire is given by:

#Substitute for
to obtain:

Solve for
:
![\theta=sin^{-1}[\frac{IlB}{mg}]](https://tex.z-dn.net/?f=%5Ctheta%3Dsin%5E%7B-1%7D%5B%5Cfrac%7BIlB%7D%7Bmg%7D%5D)
We the substitute the numerical values to calculate the equilibrium angular displacement:
![\theta= sin^{-1}[\frac{0.2A\times0.52m\times 0.040T}{0.003\ kg\times9.8m/s^2}]\\\\=8.1345\textdegree](https://tex.z-dn.net/?f=%5Ctheta%3D%20sin%5E%7B-1%7D%5B%5Cfrac%7B0.2A%5Ctimes0.52m%5Ctimes%200.040T%7D%7B0.003%5C%20kg%5Ctimes9.8m%2Fs%5E2%7D%5D%5C%5C%5C%5C%3D8.1345%5Ctextdegree)
Hence, the equilibrium angular displacement of the wire from vertical if the horizontal magnetic field is 8.1345°