Answer:
4.42 x 10⁷ W/m²
Explanation:
A = energy absorbed = 500 J
η = efficiency = 0.90
E = Total energy
Total energy is given as
E = A/η
E = 500/0.90
E = 555.55 J
t = time = 4.00 s
Power of the beam is given as
P = E /t
P = 555.55/4.00
P = 138.88 Watt
d = diameter of the circular spot = 2.00 mm = 2 x 10⁻³ m
Area of the circular spot is given as
A = (0.25) πd²
A = (0.25) (3.14) (2 x 10⁻³)²
A = 3.14 x 10⁻⁶ m²
Intensity of the beam is given as
I = P /A
I = 138.88 / (3.14 x 10⁻⁶)
I = 4.42 x 10⁷ W/m²
Answer:
t = 1964636.542 sec
Explanation:
Given data:
sphere diameter is 10 mm
Density is 1150 kg/m^3
viscosity 105 N s/m^2
We knwo that time taken by sphere can be calculated by following procedure
Solving for du
Answer:
A ball when from moving to stoping
Explanation:
Kinetic = energy of motion
Potential = energy stored
When you roll a ball on the ground, it gains kinetic energy, but then the ball starts to slow down until it stops and it remains at rest which means it's at potential energy. It went from moving (kinetic) to stoping (potential)
Hope this helped!
Have a supercalifragilisticexpialidocious day!
Answer:
D. 15 m/s downward
Explanation:
v = at + v₀
v = (-9.8 m/s²) (1.5 s) + (0 m/s)
v = -14.7 m/s
Rounded to two significant figures, the answer is D, 15 m/s downward.
