Answer:
6
because when you subtract 6 from 6 you get 0
6 - 6 = 0
well it would be 18/9 and that would simplify to 2 because if u divide both by 9 u get 2/1 which is 2
Answer:
yes, the given relation is a function.
Step-by-step explanation:
The given relation is
{(–3, –2), (–1, 0), (1, 0), (5, –2)}
A relation is called function if each element of the domain is paired with exactly one element of the range.
It means for each value of x there exist a unique value of y.
In the given relation for each value of x there exist a unique value of y.
Therefore the required solution is yes and this relation is a function.
I will show you the steps on how you get that answer and if you have any questions after that let me know and I'd be more than happy to help answer them for you.
The first step for solving (1 + y)² is to use the equation (a + b)² = a² + 2ab + b² to expand the expression.
1² + 2 × 1y + y²
1 raised to any power equals 1,, so remove the power.
1 + 2 × 1y + y²
Calculate the product of 2 × 1y.
1 + 2y + y²
Finally,, use the commutative property to reorder the terms.
y² + 2y + 1
Let me know if you have any further questions.
:)
The intervals are given as follows:
- In range notation: [-282, 20,320].
- In set-builder notation: {x|x ∈ ℝ, -282 <= x <= 20,320}
<h3>What is the range of elements notation for interval?</h3>
The range of elements notation for interval is given by:
[a,b].
In which:
In this problem these values are given by:
a = -282, b = 20,320.
Hence the interval in range notation is given by:
[-282, 20,320].
<h3>How to write the interval in set-builder notation?</h3>
The same interval can be written as follows, using set-builder notation?
{x|x ∈ ℝ, a <= x <= b}
Hence, for the situation described in this problem, the set-builder notation for the values is:
{x|x ∈ ℝ, -282 <= x <= 20,320}
More can be learned about notation of intervals at brainly.com/question/27896097
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