What are all the factors of 32? A 2, 4, 8, 16 B 1, 2, 16, 32 C 1, 2, 4, 8, 16, 32 D 2, 4, 6, 8, 12, 16, 32

Mathematics

2 answers:

Natasha2012 [34]3 years ago

4 0

What are all the factors of 32?

answer : ( C ) 1, 2, 4, 8, 16 and 32.....

melamori03 [73]3 years ago

3 0

Answer:

The factors of 32 are 1, 2, 4, 8, 16, 32

Step-by-step explanation:

The quickest way to find the factors of a number is to divide it by the smallest prime number (bigger than 1) that goes into it evenly with no remainder. Continue this process with each number you get, until you reach 1.

Find all the numbers less than or equal to the given number.
Divide the given number by each of the numbers.
The divisors that give the remainder to be 0 are the factors of the number

-------------------------------------------------------------------------------------------------------------

1 x 32 = 32
2 x 16 = 32
4 x 8 = 32
8 x 4 = 32
16 x 2 = 32

Therefore the answer is C. 1,2,4,8,16,32

You might be interested in

Solve algebraically:

vichka [17]

<h3>Answer:</h3>

$a)\ x_1=-9,\ x_2=9\\\\b)\ x_1=1,\ x_2=5$

<h3>Step-by-step explanation:</h3>

<u>Given equations:</u>

$a)\ 2x^2 - 162 = 0\\\\b) -\dfrac{1}{2}(x-3)^2=-2$

A) 2x² - 162 = 0

Step 1: Divide both sides by 2.

<h3> $\\\implies \dfrac{2x^2 - 162}{2} = \dfrac{0}{2}\\\\\implies x^2-81=0\\\\\implies x^2=81$ </h3>

Step 2: Take the square root of both sides (using both the positive and negative roots).

$\\\implies \sqrt{x^2}=\sqrt{81}\\\\\implies x=\pm\ 9$

Step 3: Separate into two cases.

$\implies x_1 = -9,\ x_2 =-9$

----------------------------------------------------------------------------------------------------------------

B) -1/2(x - 3)² = -2

Step 1: Multiply both sides by -2.

$\\\implies -2\left(-\dfrac{1}{2}(x-3)^2\right)=-2(-2)\\\\\implies (x-3)^2=4$

Step 2: Take the square root of both sides (using both the positive and negative roots).

$\\\implies\sqrt{(x-3)^2}=\sqrt{4}\\\\\implies x-3=\pm\ 2$

Step 3: Separate into two cases and solve each one. $1)\ x-3=-2\implies x=-2+3\implies \boxed{x=1}\\\\2)\ x-3=2\implies x=2+3\implies \boxed{x=5}$