Are you sure the question is correct? From a list of integers, if you pick one number, it's guaranteed to be an integer...
Surely there's a condition that you haven't mentioned?
Answer:
Option (c) : f' (x) = - 2 / 5x
Answer:
There doesn't seem to be numbers to answer that, do you have the question right? If it was a difference of 18, for example, the numbers would be 64 and 36.
Step-by-step explanation:
Find 2 numbers that added together, equal 10.
91
82
73
64
55
46
37
28
19
Then subtract them by their opposites. Find the numbers with the difference of 12.
91 - 19 = 72
82 - 28 = 54
73 - 37 = 36
64 - 46 = 18
55 - 55 = 0
46 - 64 = -18
37 - 73 = -36
28 - 82 = -54
19 - 91 = -72
There is no numbers with the difference of 12.
If it was a difference of 18, for example, the numbers would be 64 and 36.
Answer:
The greatest common factor of 42, 60 and 78 is 6.
Step-by-step explanation:
The given numbers are : 42, 60 and 78
On Prime Factorization of the given terms, we get:
42 = 2 x 3 x 7
60 = 2 x 2 x 3 x 5
78 = 2 x 3 x 13
The common factors to all these three terms is 2 x 3 = 6
Hence, the greatest common factor of 42, 60 and 78 is 6.
Answer:
<em>y=</em><em>1</em><em>/</em><em>3</em><em> </em><em>would </em><em>be </em><em>the </em><em>correct</em><em> </em><em>answer</em><em> </em><em>as </em><em>long </em><em>as </em><em>the </em><em>x </em><em>is </em><em>not </em><em>only </em><em>attached</em><em> to</em><em> the</em><em> </em><em>three,</em><em> </em><em>but </em><em>1</em><em>/</em><em>3</em><em> </em><em>as </em><em>a </em><em>whole</em><em>.</em><em> </em><em>I </em><em>hope</em><em> </em><em>this </em><em>helps!</em>