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sammy [17]
3 years ago
10

What are all the factors of 32? A 2, 4, 8, 16 B 1, 2, 16, 32 C 1, 2, 4, 8, 16, 32 D 2, 4, 6, 8, 12, 16, 32

Mathematics
2 answers:
Natasha2012 [34]3 years ago
4 0

What are all the factors of 32?

answer : ( C ) 1, 2, 4, 8, 16 and 32.....

melamori03 [73]3 years ago
3 0

Answer:

The factors of 32 are 1, 2, 4, 8, 16, 32

Step-by-step explanation:

The quickest way to find the factors of a number is to divide it by the smallest prime number (bigger than 1) that goes into it evenly with no remainder. Continue this process with each number you get, until you reach 1.

  1. Find all the numbers less than or equal to the given number.
  2. Divide the given number by each of the numbers.
  3. The divisors that give the remainder to be 0 are the factors of the number

-------------------------------------------------------------------------------------------------------------

  • 1 x 32 = 32
  • 2 x 16 = 32
  • 4 x 8 = 32
  • 8 x 4 = 32
  • 16 x 2 = 32

Therefore the answer is C. 1,2,4,8,16,32

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lozanna [386]
The triangle <span>pyramid</span>  is made up of 4 triangles.

------------------------------------
Formula:
------------------------------------
Area of triangle = 1/2 x base x height

------------------------------------
Area of the bottom triangle:
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Area = 1/2 x 9 x 7.8
Area = 35.1 yd²

------------------------------------
Area of the 3 side triangles:
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Area = 3 [ 1/2 x 9 x 10 ]
Area = 135 yd²

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Total Area:
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Total Area = 135 + 35.1 
Total Area = 170.1 yd²

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Answer: Surface Area = 170.1 yd².
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4 0
4 years ago
What is the value of x? inscribed angles
Flura [38]

The value of x is 84°.

Solution:

Measure of intercepted arc = 168°

Measure of angle x = ?

<u>Tangent-chord relationship:</u>

<em>If a tangent and a chord intersect at a point, then the measure of each angle formed is half of the measure of its intercepted arc.</em>

$\Rightarrow \angle x = \frac{1}{2}\times 168^\circ

$\Rightarrow \angle x = 84^\circ

The value of x is 84°.

8 0
4 years ago
Find the perimeter of a quadrilateral with vertices at C (-1, 2), D (-2, -1), E (2, -2), and F (1, 1). Round your answer to the
babymother [125]

Answer:

B 12.68

Step-by-step explanation:

you will need to find the distance between each segment-

so the length of DC, CF, FE, ED

d=\sqrt{(x_{2}-x_{1})  ^{2}+(y_{2}-y_{1})  ^{2}  }

DC:

D(-2,-1) C(-1,2)

d=\sqrt{(-1--2)^{2} +(2--1)^{2} } \\d=\sqrt{1^{2}+3^{2}  } \\d=\sqrt{10} =3.16

CF:

C(-1,2) F(1,1)

d=\sqrt{(1--1)^{2} +(1-2)^{2} } \\d=\sqrt{2^{2}+-1^{2}  } \\d=\sqrt{4+1} \\d=\sqrt{x} 5=2.24

FE

F(1,1) E(2,-2)

d=\sqrt{(2-1)^{2} +(-2-1)^{2} } \\d=\sqrt{1^{2} +(-3)^{2} } \\d=\sqrt{1+9} \\d=\sqrt{10}= 3.16

ED

E(2,-2) D(-2,-1)

d=\sqrt{(-2-2)^{2} +(-1--2)^{2} } \\d=\sqrt{(-4)^{2}+1^{2}  } \\d=\sqrt{16+1} \\d=\sqrt{17}= 4.12\\

3.16+2.24+3.16+4.12= 12.68

4 0
3 years ago
Expand (2 + a)9 using Pascal’s triangle.
Natalija [7]

Answer:

Step-by-step explanation:

The Pascal triangle is used to determine the coefficients of the terms when we expand the expression.

                                             1                                (A + B) ^ 0 = 1

                                         1       1                            (A +B ) ^ 1 = 1A + 1B

                                   1          2        1          (A+ B) ^ 2 = 1A^2 + 2 AB + 1B^2

By extending the triangle, you will get the 9th row, which is your expression, of the coefficients. that is

1          9       36    84    126    126    84    36    9    1

Now, fill in AB in the gaps.

1AB + 9 AB + 36AB + 84AB + 126AB + 126AB +84AB + 36AB + 9AB + 1AB

Next, you need to go from the left to fill out the exponent of A and it will go down from 9 (the exponent of the whole thing) . That is

1A^9B+9A^8B+36A^7B+84A^6B+126A^5B+126A^4B+84A^3B+36A^2B+9A^1B+1A^0B

Next will be the exponent of B. this time, you go from the right and do the same with A. You can go from the left also, but go up from 0 to 9 for the exponent of B

1A^9B^0+9A^8B^1+36A^7B^2+84A^6B^3+126A^5B^4+126A^4B^5+84A^3B^6+36A^2B^7+9A^1B^8+1A^0B^9

The last step is just to simplify the A^0=1 and B^0 =1 at the first and the last terms.

A^9+9A^8B^1+36A^7B^2+84A^6B^3+126A^5B^4+126A^4B^5+84A^3B^6+36A^2B^7+9A^1B^8+B^9

Hope you can learn the method

5 0
3 years ago
For the second problem do I add, divide, subtract or multiplied
MA_775_DIABLO [31]
Divide hope it helps
8 0
3 years ago
Read 2 more answers
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