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Papessa [141]
2 years ago
10

What is the equation of a line that has a slope of 4/5 and passes through the point (-2,4)?

Mathematics
1 answer:
SOVA2 [1]2 years ago
7 0

Answer:

y = \frac{4}{5}x + 5\frac{3}{5}

Step-by-step explanation:

Let's do it in slope-intercept form, it will look like this:

m = slope

b = y -intercept

To find our equation we will plug in the slope, plug in the point given, and solve for b.

y = mx + b

y = \frac{4}{5}x + b

4 = \frac{4}{5}(-2) + b

4 = -\frac{8}{5} + b

5\frac{3}{5} = b

Plug the b into our original equation, and there is our answer!

y = \frac{4}{5}x + 5\frac{3}{5}

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Let u = <-4, 3>. Find the unit vector in the direction of u, and write your answer in component form. (2 points)
lana66690 [7]

Answer:  < -4/5,  3/5>

This is equivalent to writing < -0.8, 0.6 >

======================================================

Explanation:

Draw an xy grid and plot the point (-4,3) on it. Draw a segment from the origin to this point. Then draw a vertical line until reaching the x axis. See the diagram below.

We have a right triangle with legs of 4 and 3. The hypotenuse is \sqrt{4^2+3^2} = \sqrt{16+9} = \sqrt{25} = 5 through use of the pythagorean theorem.

We have a 3-4-5 right triangle.

Therefore, the vector is 5 units long. This is the magnitude of the vector.

Divide each component by the magnitude so that the resulting vector is a unit vector pointing in this same direction.

Therefore, we go from < -4, 3 > to < -4/5,  3/5 >

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Side note: Unit vectors are useful in computer graphics.

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