Question

What is the equation of a line that has a slope of 4/5 and passes through the point (-2,4)?

Answer 1

Answer:

y = $\frac{4}{5}$x + 5$\frac{3}{5}$

Step-by-step explanation:

Let's do it in slope-intercept form, it will look like this:

m = slope

b = y -intercept

To find our equation we will plug in the slope, plug in the point given, and solve for b.

y = mx + b

y = $\frac{4}{5}$x + b

4 = $\frac{4}{5}$(-2) + b

4 = $-\frac{8}{5}$ + b

5$\frac{3}{5}$ = b

Plug the b into our original equation, and there is our answer!

y = $\frac{4}{5}$x + 5$\frac{3}{5}$