What is the equation of a line that has a slope of 4/5 and passes through the point (-2,4)?

Mathematics

1 answer:

SOVA2 [1]1 year ago

7 0

Answer:

y = $\frac{4}{5}$ x + 5 $\frac{3}{5}$

Step-by-step explanation:

Let's do it in slope-intercept form, it will look like this:

m = slope

b = y -intercept

To find our equation we will plug in the slope, plug in the point given, and solve for b.

y = mx + b

y = $\frac{4}{5}$ x + b

4 = $\frac{4}{5}$ (-2) + b

4 = $-\frac{8}{5}$ + b

5 $\frac{3}{5}$ = b

Plug the b into our original equation, and there is our answer!

y = $\frac{4}{5}$ x + 5 $\frac{3}{5}$

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5 0

2 years ago

Read 2 more answers

A train goes twice as fast downhill as it can go uphill, and 2/3 feet as fast uphill as it can go on level ground. If it goes 12

Yuri [45]

Answer:

0.5hrs

Step-by-step explanation:

Let the speed downhill be $x$ ,

Speed uphill is $0.5x$ . We are told than speed uphill is $\frac{2}{3}$ the speed on flat ground. Therefore the speed on level ground will be $\frac{0.5x}{2/3}=0.75x$ .