Question

A stone is dropped from a cliff. After it has fallen 10 m, what is the stones velocity?

Answer 1

Answer:

${v}^{2} = {u}^{2} + gs \\ {v}^{2} = {0}^{2} + (9.8)(10) \\ {v}^{2} = 98 \\ v = \sqrt{98} \: m. {s}^{ - 1} \\ v = 9.899 \approx10 \: m. {s}^{ - 1} (2 \: s \: f)$