Question

A car of mass 2400kg accelerates from 10m/s to 30m/s if the force is 12000N what is the distance​

Answer 1

Explanation:

• Initial velocity (u) = 10 m/s
• Final velocity (v) = 30 m/s
• Mass (m) = 2400 kg
• Force (F) = 12000 N

Let us find the time taken first.

→ F = ma

• Acceleration (a) = (v – u)/t

→ 12000 = 2400 × (30 – 10)/t

→ 12000 ÷ 2400 = (20)/t

→ 5 = 20/t

→ 5t = 20

→ t = 20 ÷ 5

→ t = 4 seconds

Now, find the acceleration.

→ a = (v – u)/t

→ a = (30 – 10)/4

→ a = 20/4

→ a = 5 m/s²

Now, by using the third equation of motion,

→ v² – u² = 2as

• s = distance

→ (30)² – (10)² = 2 × 5 × s

→ 900 – 100 = 10s

→ 800 = 10s

→ 800 ÷ 10 = s

→ 80 m = s

Therefore, distance travelled is 80 m.