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horsena [70]
4 years ago
5

Between 1965 and 1980, the world population grew at an annual rate of 2%. Using the rule of 72, population is expected to double

in
Mathematics
1 answer:
Fiesta28 [93]4 years ago
4 0

Answer:

The population is expected to double in 36 years

Step-by-step explanation:

According to the the rule of 72,

A value is doubled if the product of the annual rate and number of years is 72,

Given,

The annual rate of interest = 2%

Let x be the time in years after 1965,

By the above statement,

The population will double if,

x × 2 = 72 ⇒ x = 36

Hence, the after 36 years since 1965 the population will be doubled,

i.e in 2001.   ( ∵ 36 years after 1965 )

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Find the surface area of the composite figure​
Gnoma [55]

Answer:

=280 in^2

Step-by-step explanation:

----------------------------------------

Let's find the surface area of the pink rectangular prism first.

2*10=20+20=40

4*10=40+40=80

4*2=8+8=16

40+80+16=136

The surface area for the pink rectangular prism is 136 in^2.

-------------------->>>>>

Now, let's find the surface area of the green rectangular prism.

4*7=28+28=56

4*7=28+28=56

4*4=16+16=32

56+56+32=144

The surface area for the green rectangular prism is 144 in^2.

-------------------->>>>>

Now let's add the surface area of both rectangular prisms to find the surface area of the composite figure.

136+144=

=280 in^2

----------------------------------------

Hope this is helpful.

6 0
3 years ago
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Find the volume of each cylinder. Use 3.14 for pi. Round your answer to the nearest tenth
otez555 [7]

Answer:

V ≈471.24 mm^3

Step-by-step explanation:

The formula for cylinder volume is πr^2 x h, so ((π x 25) x h). That's just 25π x 6. That is about 471.238898, which rounded is almost 471.24. Or, in terms of π, you could leave your answer as 150π mm^3

8 0
3 years ago
Pls HELP, im stuck(picture included)
Verdich [7]
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5 0
3 years ago
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Evaluate. 5x{(9 +2) X (6 + 3)} + 15​
Tju [1.3M]

Answer:15(3x11^+1)

Step-by-step explanation:

4 0
3 years ago
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Compute the lower Riemann sum for the given function f(x)=x2 over the interval x∈[−1,1] with respect to the partition P=[−1,− 1
Nata [24]

Answer:

21/64

Step-by-step explanation:

First, we need to note that the function f(x) = x² is increasing on (0, +∞), and it is decreasing on (-∞,0)

The first interval generated by the partition is [-1, -1/2], since f is decreasing for negative values, we have that f takes its minimum values at the right extreme of the interval, hence -1/2.

The second interval is [-1/2, 1/2]. Here f takes its minimum value at 0, because f(0) = 0, and f is positive otherwise.

Since f is increasing for positive values of x, then, on the remaining 2 intervals, f takes its minimum value at their respective left extremes, in other words, 1/2 and 3/4 respectively.

We obtain the lower Riemman sum by multiplying this values evaluated in f by the lenght of their respective intervals and summing the results, thus

LP(f) = f(-1/2) * ((-1/2) - (-1)) + f(0) * (1/2 - (-1/2)) + f(1/2)* (3/4 - 1/2) + f(3/4) * (1- 3/4)

= 1/4 * 1/2 + 0 * 1 + 1/4 * 1/4 + 9/16 * 1/4 = 1/8 + 0 + 1/16 + 9/64 = 21/64

As a result, the lower Riemann sum on the partition P is 21/64

3 0
3 years ago
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