Add up all.
Yards = 29 + 55 + 13 = 97
Feet = 2 + 1 + 1 = 4
Inches = 11 + 10 + 3 = 24
In conclusion your final anwser is
97 yd. 4 ft. 24 in.
Hope this helps!
Have a great day.
<u>x-3</u>
x+7
its suppose to be at fraction
⓵ To calculate the volume of a right circular cylinder, the formula is π times the radius of the circular base² time the height of the cylinder.
⓶ Now that we know that the equation to calculate the volume of a right circular cylinder is :
V = π x (r²) x h
You need to find the numbers to replace the volume (V) and the height (h) in the formula.
We already know that the volume is 320 square feet and that the height is 20 feet.
So we are left with a formula looking like this :
320 = π x (r²) x 20
⓷ Now we need to find the radius of the circular base! To do so, you need to solve this equation and isolate the “r”. Start by simplifying the right side :
320 = π x (r²) x 20
÷20 ÷20
↓
16 = π x r²
÷π ÷π
↓
5,09 ⋍ r²
√ √
↓
2,26 feet ⋍ r
⓸ Now that we knoe the value of the radius of the circular base, all there’s left to do is multiply this number by two in order to find the diameter of the water tank :
2,26 x 2 = d
↓
4,51 feet ⋍ d
So your final answer is : the diameter of the water tank is about 4,51 feet.
** Since I devided by “π”, all the answers I wrote from that point are rounded to the nearest hundredths just to make things easier to visualize, but I kept all of the decimals when doing the calculations. So it is possible that your answer might differ slightly from mine if you use the rounded numbers to calculate everything. Just keep that in mind!
I hope this helped, if there’s anything just let me know! ☻
The height of the blue spruce was 45.
We find the mean by adding all of the data points and dividing by the number of data points. We will add the unknown value x and change the number we're dividing by to 7:
(160+320+100+110+200+220+x)/7 = 165
(1110+x)/7 = 165
Multiply both sides by 7:
1110 + x = 1155
Subtract 1110 from both sides:
x = 45
Answer:
true
Step-by-step explanation:
a square will always be a rectangle but a rectangle will not always be a square.
