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2 years ago

12

my daughter is having trouble with some homework. the question is, " how to write the number 21,054 using ONLY hundreds, tens an

d ones in 3 different ways. HELP!

1 answer:

Rasek [7]2 years ago

5 0

One way could be 210 hundreds, 5 tens, and 4 ones. I will think of others but for now hope this helps

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Lenox ironed 1/4 of the shirts over the weekend. She plans to split the remainder of the work equally over the next 5 evenings.

MrMuchimi

3/20, or 0.15 of the shirts each evening

1 - 1/4 = 3/4

(3/4) / 5 = (3/4) / (5/1) = (3/4) x (1/5) = 3/20 = 0.15

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2 years ago

Read 2 more answers

A. Identify the percentage, rate and base.

Finger [1]

Answer:

1. rate = 30, base = 40, percentage = 12

2. rate = 6, base = 24, percentage = 25

3. rate = 16, base = 64, percentage = 25

4. rate = 4, base = 50, percentage = 20

5. rate = 75, base = 80, percentage = 60

Step-by-step explanation:

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2 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

Verify that P = Ce^t /1 + Ce^t is a one-parameter family of solutions to the differential equation dP dt = P(1 − P).

NemiM [27]

Answer:

See verification below

Step-by-step explanation:

We can differentiate P(t) respect to t with usual rules (quotient, exponential, and sum) and rearrange the result. First, note that

$1-P=1-\frac{ce^t}{1+ce^t}=\frac{1+ce^t-ce^t}{1+ce^t}=\frac{1}{1+ce^t}$

Now, differentiate to obtain

$\frac{dP}{dt}=(\frac{ce^t}{1+ce^t})'=\frac{(ce^t)'(1+ce^t)-(ce^t)(1+ce^t)'}{(1+ce^t)^2}$

$=\frac{(ce^t)(1+ce^t)-(ce^t)(ce^t)}{(1+ce^t)^2}=\frac{ce^t+ce^{2t}-ce^{2t}}{(1+ce^t)^2}=\frac{ce^t}{(1+ce^t)^2}$

To obtain the required form, extract a factor in both the numerator and denominator:

$\frac{dP}{dt}=\frac{ce^t}{1+ce^t}\frac{1}{1+ce^t}=P(1-P)$

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2 years ago