Answer : The enthalpy change for converting 1 mole of ice at 
to water at 
is, 7.712 KJ
Solution :
Process involved in the calculation of enthalpy change :
Now we have to calculate the enthalpy change.
![\Delta H=[m\times c_{ice}\times (T_2-T_1)]+\Delta H_{fusion}+[m\times c_{water}\times (T_3-T_2)]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5Bm%5Ctimes%20c_%7Bice%7D%5Ctimes%20%28T_2-T_1%29%5D%2B%5CDelta%20H_%7Bfusion%7D%2B%5Bm%5Ctimes%20c_%7Bwater%7D%5Ctimes%20%28T_3-T_2%29%5D)
where,
= enthalpy change
m = mass of water = 
= specific heat of ice = 2.09 J/gk
= specific heat of water = 4.18 J/gk
= enthalpy change for fusion = 6.01 KJ/mole = 0.00601 J/mole
conversion : 
= initial temperature of ice =
= final temperature of ice = 
= initial temperature of water =
= final temperature of water = 
Now put all the given values in the above expression, we get
![\Delta H=[18g\times 2.09J/gK\times (273-248)k]+0.00601J+[18g\times 4.18J/gK\times (363-273)k]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5B18g%5Ctimes%202.09J%2FgK%5Ctimes%20%28273-248%29k%5D%2B0.00601J%2B%5B18g%5Ctimes%204.18J%2FgK%5Ctimes%20%28363-273%29k%5D)
(1 KJ = 1000 J)
Therefore, the enthalpy change for converting 1 mole of ice at to water at is, 7.712 KJ
Answer:
B
Explanation:
changing color is a form of a physical change
Explanation:
It is more difficult to remove electrons from the second shell or energy level because of the imbalance between the positive nuclear charge and the remaining electrons.
- The amount of energy required to remove electrons in ground state of an atom is the ionization energy.
- The first ionization energy is the energy needed to remove the most loosely bound electron of an atom in the gas phase in ground state.
- The second energy has a greater nuclear pull as it is closer to the nucleus.
- Both potassium and silicon have the same number of energy levels.
Test tubes heat small amounts of liquids while boiling tube boils liquids
Single displacement and combustion reactions are ALWAYS redox.
