1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
tatiyna
3 years ago
5

How many electrons does hydrogen need to satisfy the octet rule?

Chemistry
1 answer:
quester [9]3 years ago
4 0
Just 2 valence electrons.

Hydrogen already has one to start with, as well. With the exception of hydrogen and helium, all other atoms need 8 valence e-
You might be interested in
What is the area on the earth's surface directly above where an earthquake originates?
Natalija [7]

Answer:

The epicenter

5 0
3 years ago
Which subatomic particle has negligible mass and travels around outside the nucleus?
allsm [11]
The electron is a subatomic particle that has a negative charge and a negligible mass. The electron travels around out side the nucleus.

The subatomic particles that are inside the nucleus are protons and neutrons.

The answer to your question is electron. 
7 0
3 years ago
Read 2 more answers
If 15.0 mL of phosphoric acid completely neutralizes 38.5 mL of 0.150 mol/L calcium hydroxide, what is the concentration of the
Sedbober [7]

Answer:

Let me give it a try.

H3PO4 + Ca(OH)2 = Ca3(PO4)2 + H2O

Balancing this reaction

2H3PO4 + 3Ca(OH)2 == Ca3(PO4)2 + 6H2O.

Moles= Molarity x Volume

Volume = 38.5ml = 0.0385L

Moles of Ca hydroxide = 0.150m/L x 0.0385L

(Notice the units canceling out...leaving moles).

=0.005775moles of Ca(OH)2.

From balanced reaction...

3moles of Ca(OH)2 completely reacts with 2moles of H3PO4

0.005775moles of Ca(OH)2 would completely react with....

= 0.005775 x 2/(3)

=0.00385moles of H3PO4.

Now we're looking for its Concentration in Mol/L

Molarity=Moles of solute/Volume of solution(in L)

Volume of solution assuming no other additions to the reaction = 15ml + 38.5ml =53.5ml =0.0535L

Molarity = 0.00385/0.0535

=0.072Mol/L.

If this is wrong

then Simply Try The formula for Mixing of solutions

C1V1 = C2V2

0.15 x 38.5 = C2 x (15+38.5)

C2 = 0.11M/L.

7 0
3 years ago
PLEASE HELP!!!!
Colt1911 [192]

c. table salt is a metalloid with properties of both reactants

4 0
3 years ago
Kepler’s second law of planetary motion states which of the following?
aev [14]
Kepler stated three laws of planetary motion.

First law states that the pathway of a planet is an ellipse with the Sun at one of the foci.

Second law states that an imaginary line joining the Sun and a planet sweeps out equal areas during equal lengths of time.

Third law states that the square of the period of the orbit of a planet is directly proportional to the cube of the length of the distance from the Sun.

Therefore, the answer is that Kepler's second law of planetary motion states that planets cover the same area during equal time periods.
6 0
3 years ago
Other questions:
  • Use Dimensional Analysis:
    13·1 answer
  • What is always true of a weak acid ?
    9·2 answers
  • Match the element with its description. Match Term Definition Potassium A) Has properties of both metals and nonmetals Barium B)
    14·1 answer
  • Problem 12.002 the molar analysis of a gas mixture at 30°c, 2 bar is 40% n2, 50% co2, 10% ch4. determine
    11·1 answer
  • Do you think a single gene controls height in humans, as it does in peas? Explain your answer.
    7·2 answers
  • Do all titrations of a strong base with a strong acid have the same ph at the equivalence point?
    5·1 answer
  • Write complete ionic equation to show the reaction of aqueous lead(II) nitrate with aqueous potassium sulfate to form solid lead
    11·2 answers
  • At a certain temperature the rate of this reaction is first order in SO₃ with a rate constant of 0.208 s⁻¹:
    8·1 answer
  • Match the molecular shapes to the correct Lewis structures
    11·2 answers
  • Please help! its due at the end of class.
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!