Answer : (C) Hafnium is the most likely identity of the given substance.
Solution : Given,
Mass of given substance (m) = 46.9 g
Volume of given substance (V) = 3.5 
First, find the Density of given substance.
Formula used :
Now,put all the values in this formula, we get
= 13.4 g/
So, we conclude that the density of given substance (13.4 g/) is approximately equal to the density of Mercury and Hafnium (13.53 and 13.31 g/ respectively).
According to the question the substance is solid at room temperature but Mercury is liquid at room temperature. So, Mercury is not identical to the given substance.
Another element i.e, Hafnium is the element whose density is approximately equal to the given substance and also solid at room temperature. And we know that the melting point of solid is high.
So, Hafnium is the most likely element which is the identity of the given substance.
Answer:
CO(g) + H2(g) + H2O(g) ==> CO2(g) + 2H2(g)
Explanation:
In the industry, hydrogen is prepared from water and hydrocarbons. Water gas being the major method of preparation of hydrogen industrially.
The water-gas reaction is an industrial process in which steam is passed over red-hot coke giving a gaseous mixture of carbon monoxide and hydrogen:
C + H2O(g) → CO + H2.
The mixture of CO and H2 is Futher passed through steam according to the equation:
CO(g) + H2(g) + H2O(g) ==> CO2(g) + 2H2(g) to give hydrogen and carbon dioxide.
Answer:
it will float if the object is 1g/cm^3(water 's density ) because it is less dense
Answer:
2.6×10^-19 J/photon
Explanation:
E of photon = h × ν
where h= 6.63 × 10^-34 j.s
v= C ÷ λ
E = ( h × c) ÷ λ
E = (6.63 × 10^-34 × 3.00
×10^8 ) ÷ ( 765 × 10^-9)
E = 2.6×10^-19 J/photon
540 nm is the answer ! can you help me out please ? it is a science question add me and message me :)
