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3 years ago

12

Identify the acid, base, conjugate acid and conjugate base in the following reactions:

1 answer:

Leni [432]3 years ago

4 0

Answer:

a. NH₃ : base

CH₃COOH (acetic acid) : acid

NH₄⁺ : conjugate acid

CH₃COO⁻ : conjugate base

b. HClO₄ (perchloric acid) : acid

NH₃ : base

ClO₄⁻ : conjugate base

NH₄⁺ : conjugate acid

Hope this helps.

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Calculate the empirical formula for each of the following natural flavors based on their elemental mass percent composition.

tamaranim1 [39]

Answer:

Nitroglycerin- CNH2O3

Vanilin- C3H3O

Explanation:

The empirical formula is the simplest formula of a compound. It depicts the ratio of atoms of each element in the compound. It can be obtained by dividing the percentage by mass of each element by its relative atomic mass. The lowest ratio obtained is now used to divide all the previously obtained ratios and whole number values are recorded. This shows the ratio of atoms of each element present, hence the empirical formula.

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4 years ago

Calculate the ratio of the mass ratio of SS to OO in SOSO to the mass ratio of SS to OO in SO2SO2. Consider a sample of SOSO in

Veronika [31]

Answer:

The ratio of the mass ratio of S to O; in SO, to the mass ratio of S to O; in SO₂, is 2:1

Explanation:

According to the consideration, let us first find the ratio of S and O in both the compounds

For SO:

$\frac{m_{S} }{m_{O} }= \frac{32}{16}\\\\ \frac{m_{S} }{m_{O} }= 2$

Let us express it as

$SO_{\frac{m_{S} }{m_{O} }} = 2$

For SO₂,

Due to two oxygen atoms in the molecule, the mass of oxygen will be taken two times

$\frac{m_{S} }{m_{O} }= \frac{32}{(2)(16)}\\\\ \frac{m_{S} }{m_{O} }= 1$

Let us express it as

$SO_2_{\frac{m_{S} }{m_{O} }}= 1$

Now, for the ratio of both the above-calculated ratios,

$\frac{SO_{\frac{m_{S} }{m_{O} }}}{SO_2_{\frac{m_{S} }{m_{O} }}}=\frac{2}{1}$

The required ratio is 2:1

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3 years ago

What conclusion about bonding can be drawn from these diagrams?

padilas [110]

Answer:

It’s b

Explanation:

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TRUE

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