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slavikrds [6]
4 years ago
14

PLEASE HELP!!!!!

Mathematics
1 answer:
Rainbow [258]4 years ago
7 0

Answer:

Option: A(0.585)

Step-by-step explanation:

After arranging our data in ascending order we get that:

5.16   5.16   5.25   5.33   5.33   5.5   5.66   5.66   5.75   5.75   6   6   6.25

Quartiles divide a rank-ordered data set into four equal parts. The values that divide each part are called the first, second, and third quartiles; and they are denoted by Q1, Q2, and Q3, respectively.


  • Q_1 is the "middle" value in the first half of the rank-ordered data set.

  • Q_2 is the median value in the set.

  • Q_3 is the "middle" value in the second half of the rank-ordered data set.

<em>The interquartile range is equal to Q3-Q1.</em>

So, the Median(Q_2)of data is given by: 5.66

also the lower half is:

5.16   5.16   5.25   5.33   5.33   5.5

Hence, the middle value or median of this lower half of this data lie between 5.25 and 5.33 which is 5.29.

Hence, Q_1=5.29

Similarly the upper half is:

5.66   5.75   5.75   6   6   6.25

Hence, the middle value or median of this upper half of this data lie between 5.75 and 6 which is 5.875

Hence, Q_3=5.875

Hence, the interquartile range=Q_3-Q_1=5.875-5.29=0.585

Hence, option A is correct.


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