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erma4kov [3.2K]
3 years ago
14

3. A crew team rows a boat at a rate of 20 km/h in still water. Beginning at time = 0 minutes, the team rows for 30 minutes up a

river (against the current). The speed of the current is 1.5 km/h. How long will it take the crew team to row down the river (with the current) to return to the starting point?
30 min
22 min
26 min
24 min
Physics
2 answers:
Sidana [21]3 years ago
8 0
The right answer for the question that is being asked and shown above is that: "26 min." A crew team rows a boat at a rate of 20 km/h in still water. Beginning at time = 0 minutes, the team rows for 30 minutes up a river (against the current). The speed of the current is 1.5 km/h. It will take 26 minutes the crew team to row down the river.
Sindrei [870]3 years ago
4 0
Going upstream against the current gives a net speed equivalent to the speed at still water minus the speed of the current. Consequently, the speed downstream gives a net speed equal to the speed at still water plus the speed of the current, making it travel faster. The solution is:

UPSTREAM

v = 20 - 1.5 = 18.5 km/h
t = 30 mins or 0.5 hours
distance = 18.5km/h (0.5 h) = 9.25 km

DOWNSTREAM
for the same distance of 9.25 km:

v = 20 + 1.5 = 21.5 km/h
t = 9.25km / 21.5 km/h = 0.43 hours or 25.8 mins  =  26 mins --> FINAL ANS.
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In SI units, what is the magnitude the net force acting on a 1,152 kg car that accelerates uniformly along a straight line from
geniusboy [140]

Answer:

Fnet = 14515.2 Newton

Explanation:

Net force can be defined as the vector sum of all the forces acting on a body or an object i.e the sum of all forces acting simultaneously on a body or an object.

Mathematically, net force is given by the formula;

Fnet = Fapp + Fg

Where;

  • Fnet is the net force.
  • Fapp is the applied force.
  • Fg is the force due to gravitation.

Given the following data;

Mass = 1,152 kg

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Final velocity, v = 17m/s

Time, t = 5 seconds

To find the magnitude of the net force;

First of all, we would determine the acceleration of the car.

Acceleration = (v-u)/t

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To find the applied force;

Fapp = mass * acceleration

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Fg = mass * acceleration due to gravity

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Fnet = 3225.6 + 11289.6

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