Answer:
Part (a) The magnitude of the deflection of electron beam on the screen due to the Earth's gravitational field is 5.97*
m.
Part (b) The magnitude of the deflection of electron beam on the screen due to the vertical component of the Earth's magnetic field is 
m
The point on a line through the ends of the meter stick is the electric field equal to zero is 4.7 m from the 0 cm mark.
<h3>What is electric field?</h3>
An electric field is the physical field that surrounds the electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them. It also refers to physical field for a system of charged particles. Electric fields originate from the electric charges and time-varying electric currents. Electric fields and the magnetic fields are both manifestations of the electromagnetic field, one of the four fundamental interactions (also called forces) of nature.
Electric fields are important in many areas of the physics, and are exploited in electrical technology. In atomic physics and chemistry, for the instance, the electric field is the attractive force holding the atomic nucleus and electrons together in atoms. It is also force responsible for chemical bonding between atoms that result in molecules.
The electric field is defined as a vector field that associates to each point in the space the (electrostatic or Coulomb) force per unit of charge exerted on an infinitesimal positive test charge at rest at that point. The derived SI unit for electric field is the volt per meter (V/m), which is equal to the newton per coulomb (N/C)
To know more about atoms visit: brainly.com/question/1566330
#SPJ4
The correct question will be:
"A +5.00-μC point charge is placed at 0.0 cm mark of meter stick and a -4.00-μC point charge is placed at 50.0 cm mark. At what point on a line through the ends of meter stick is electric field equal to zero?"
It is 7.4x(10 to the power of 7)
You traveled a distance of 620.075 meters if it takes you 8.5 seconds to stop.
<u>Given the following data:</u>
- Initial velocity, U = 31.3 m/s
We know that acceleration due to gravity (a) for an object is equal to 9.8 meter per seconds square.
To find the distance traveled, we would use the second equation of motion:
Mathematically, the second equation of motion is given by the formula;
Where:
- S is the distance travelled.
- u is the initial velocity.
- t is the time measured in seconds.
Substituting the parameters into the formula, we have;
<em>Distance, S</em><em> = </em><em>620.075 meters.</em>
Therefore, you traveled a distance of 620.075 meters if it takes you 8.5 seconds to stop.
Read more: brainly.com/question/8898885
