Answer:
The answer is 4
Step-by-step explanation:
Step-by-step explanation:
1 day = $ 26.95
3 days = 26.95 × 3
= $80.85
Remainder = $100 - $80.85
= $19.15
1 mile = $ 0.27
= $19.15 ÷ $0.27
= 71 miles
Answer:
This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:
"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"
Where X must be a positive number smaller than one, now we can solve it:
we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:
N = 45*(4/5) = 36
And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:
M = 36*X
now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")
M = 36*(1/2) = 18
So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.
Answer:
16
Step-by-step explanation:
61+3=64
16*4=64
64=64
Answer: t= 4 seconds
Maximum height = 256 feet
Step-by-step explanation:
The height of the object projected upwards after t seconds is given by
s(t)=-16t^2+128t.
The expression is a quadratic equation. When this equation is plotted on a graph, height against time, it takes the shape of a parabola whose vertex represents the maximum height attained by the object.
To get the value of t at the maximum height,
t = -b/2a
From the equation,
a = -16
b = 128
t = -128/-2×-16
= -128 /- 32= 4
it will take 4 seconds to reach its maximum height
To find maximum height attained, put t= 4 in the equation
s(t)=-16t^2+128t
S = -16× 4^2 + 128×4
S = -256+512
S = 256 feet
