Answer:
m(∠AOF) = 148°
Step-by-step explanation:
From the figure attached,
CD intersects line EF at a point O.
Line CD is perpendicular to the line EF.
m(∠AOE) = 32°
m(∠COE) = 90°
Since m(∠COE) = m(∠AOE) + m(∠AOC) = 90°
32° + m(∠AOC) = 90°
m(∠AOC) = 90° - 32° = 58°
m(∠AOF) = m(∠AOC) + m(∠COF)
                = 58° + 90°
                = 148°
Therefore, m(∠AOF) = 148° will be the answer.
 
        
             
        
        
        
Answer:
uhm sorry this is really hard maybe answer 2
Step-by-step explanation:
 
        
             
        
        
        
Let a = 693, b = 567 and c = 441 
Now first we will find HCF of 693 and 567 by using Euclid’s division algorithm as under 
693 = 567 x 1 + 126 
567 = 126 x 4 + 63 
126 = 63 x 2 + 0 
Hence, HCF of 693 and 567 is 63 
Now we will find HCF of third number i.e., 441 with 63 So by Euclid’s division alogorithm for 441 and 63 
441 = 63 x 7+0 
=> HCF of 441 and 63 is 63. 
Hence, HCF of 441, 567 and 693 is 63.
        
             
        
        
        
Solution :
Given 


Let the initial approximation is 
So by Newton's method, we get






 are identical up to eight decimal places.
 are identical up to eight decimal places.
The approximate real root is x ≈ 1.32471795
∴ x = 1.32471795