Given: distance 1 d₁ = 40 m; distance 2 d₂ = 3.8 m g = -9.8 m/s²
Initial Velocity Vi = 0 Final Velocity of stone 2 is unknown = ?
Total distance dₓ = d₁ - d₂ = 40 m - 3.8 m = 36.2 m
Formula: a = Vf² - Vi²/2d derive for Final Velocity Vf
acceleration is now due to gravity, therefore a = g
Vf = √2gd Vf = √2(9.8 m/s²)(36.2 m)
Vf = 26.64 m/s
Reason: The second stone will still start from rest.
answer: transverse and longitudinal
v = x/t
v = average velocity, x = displacement, t = elapsed time
Given values:
x = 6km south, t = 60min
Plug in and solve for v:
v = 6/60
v = 0.1km/min south
Answer: 757m/s
Explanation:
Given the following :
Mole of neon gas = 1.00 mol
Temperature = 465k
Mass = 0.0202kg
Using the ideal gas equation. For calculating the average kinetic energy molecule :
0.5(mv^2) = 3/2 nRt
Where ;
M = mass, V = volume. R = gas constant(8.31 jK-1 mol-1, t = temperature in Kelvin, n = number of moles
Plugging our values
0.5(0.0202 × v^2) = 3/2 (1 × 8.31 × 465)
0.0101 v^2 = 5796.225
v^2 = 5796.225 / 0.0101
v^2 = 573883.66
v = √573883.66
v = 757.55109m/s
v = 757m/s
