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iren [92.7K]
3 years ago
11

Which factor MOST directly affects the flow of ocean currents?

Physics
2 answers:
Kay [80]3 years ago
7 0
The factor that most affects the flow of ocean currents is B. differences in temperaturethreAnswer here
elena-s [515]3 years ago
5 0

Answer:

Correct Answer is B (Differences in temperature)

Explanation:

One of the main cause of ocean current to occur is variation of temperature of different layer of oceanic water.Water which have high temprature is less dense and this Less density water float above the surface of high density water. When this less density water reached on the surface of ocean that time wind which blows on the surface water makes the water cool or in other words we can say that water released  its heat to the surrounding environment. when water becomes cool it again shifted in downward direction and less density water  will moves upward. In this way this process will continue and hence ocean current is created.

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The Tesla Roadster electric car is rated at 16.8kW. How much energy does it use during a one hour drive? Answer in MJ
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Energy = (16,800 x 3,600) J

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Energy = 60.48 MJ

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The milky way is often considered to be an intermediately wound, barred spiral, which would be type ________ according to hubble
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An archer shoots an arrow with a mass of 45.0 grams from bow pulled
Sladkaya [172]

Answer:

The force the archer need to pull in order to achieve the height is approximately 101.8 N

Explanation:

By energy conservation principle, puling an elastic bow with a force, for a given distance, performs work which is converted to the potential energy of the arrow at height

The given parameters are;

The mass of the arrow, m = 45.0 grams = 0.045 kg

The distance the elastic bow is pulled, d = 65.0 cm = 0.65 m

The height at which the arrow is reaches, h = 150.0 meters

Let 'F', represent the force the archer need to pull in order to achieve the height

Work done, W = Force × Distance moved in the direction of the force

Therefore;

The work done in pulling the arrow, W = F × d

By energy conservation, we have;

The work done in pulling the arrow, W = The potential energy gained by the arrow, P.E.

W = P.E.

The potential energy gained by the arrow, P.E. = m·g·h

Where;

m = The mass of the arrow

g = The acceleration due to gravity = 9.8 m/s²

h = The height the arrow reaches

∴ by plugging in the values, P.E. = 0.045 kg ×9.8 m/s² × 150 m = 66.15 J

W = F × d = F × 0.065 m

Also, W = P.E. = 66.15 J

∴ W = F × 0.065 m = 66.15 J

F × 0.065 m = 66.15 J

F = 66.15 J/(0.65 m) = 1323/13 N ≈ 101.8 N

The force the archer need to pull in order to achieve the height, F ≈ 101.8 N.

3 0
2 years ago
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