All categories

3 years ago

Which factor MOST directly affects the flow of ocean currents?

Physics

2 answers:

Kay [80]3 years ago

7 0

The factor that most affects the flow of ocean currents is B. differences in temperaturethreAnswer here

elena-s [515]3 years ago

5 0

Answer:

Correct Answer is B (Differences in temperature)

Explanation:

One of the main cause of ocean current to occur is variation of temperature of different layer of oceanic water.Water which have high temprature is less dense and this Less density water float above the surface of high density water. When this less density water reached on the surface of ocean that time wind which blows on the surface water makes the water cool or in other words we can say that water released its heat to the surrounding environment. when water becomes cool it again shifted in downward direction and less density water will moves upward. In this way this process will continue and hence ocean current is created.

You might be interested in

A rope of negligible mass is wrapped around a 225-kg solid cylinder of radius 0.400 m. the cylinder is suspended several meters

emmainna [20.7K]

Let me know if you have questions

5 0

3 years ago

Help me with this please!

alexgriva [62]

Prototype
Chemistry
Technology
Troubleshooting
Hypothesis?
Observing
Variable
Hypothesis?
Engineer
System

3 0

4 years ago

7. You start to walk toward the east towards home at a constant speed of 4 km/hr. At the same time, Someone else leaves your hom

amm1812

A) position time graph for both is shown

here one of the graph is of lesser slope which means it is moving with less speed while other have larger slope which shows larger speed

At one point they intersects which is the point where they both will meet

B) Let the two will meet after time "t"

now we can say that

if they both will meet after time "t"

then the total distance moved by you and other person will be same as the distance between you and home

so it is given as

$v_1t + v_2t = d$

$4*t + 28*t = 3.2 km$

$t = \frac{3.2}{32} = 0.1 hr$

so they will meet after t = 6 min

so from position time graph we can see that two will meet after t = 6 min where at this position two graphs will intersect

4 0

4 years ago

10. A triply ionized beryllium atom is in the ground state. It absorbs energy and makes a transition to the n = 5 excited state.

Xelga [282]

Answer:

$\lambda=1282\ nm$

Explanation:

$E_n=-2.179\times 10^{-18}\times \frac{1}{n^2}\ Joules$

For transitions:

$Energy\ Difference,\ \Delta E= E_f-E_i =-2.179\times 10^{-18}(\frac{1}{n_f^2}-\frac{1}{n_i^2})\ J=2.179\times 10^{-18}(\frac{1}{n_i^2} - \dfrac{1}{n_f^2})\ J$

$\Delta E=2.179\times 10^{-18}(\frac{1}{n_i^2} - \dfrac{1}{n_f^2})\ J$

Also, $\Delta E=\frac {h\times c}{\lambda}$

Where,

h is Plank's constant having value $6.626\times 10^{-34}\ Js$

c is the speed of light having value $3\times 10^8\ m/s$

So,

$\frac {h\times c}{\lambda}=2.179\times 10^{-18}(|\frac{1}{n_i^2} - \dfrac{1}{n_f^2}|)\ J$

$\lambda=\frac {6.626\times 10^{-34}\times 3\times 10^8}{{2.179\times 10^{-18}}\times (|\frac{1}{n_i^2} - \dfrac{1}{n_f^2}|)}\ m$

So,

$\lambda=\frac {6.626\times 10^{-34}\times 3\times 10^8}{{2.179\times 10^{-18}}\times (|\frac{1}{n_i^2} - \dfrac{1}{n_f^2}|)}\ m$

Given, $n_i=5\ and\ n_f=3$

$\lambda=\frac{6.626\times 10^{-34}\times 3\times 10^8}{{2.179\times 10^{-18}}\times (\frac{1}{5^2} - \dfrac{1}{3^2})}\ m$

$\lambda=\frac{10^{-26}\times \:19.878}{10^{-18}\times \:2.179\left(|\frac{1}{25}-\frac{1}{9}\right)|}\ m$

$\lambda=\frac{19.878}{10^8\times \:2.179\left(|-\frac{16}{225}\right|)}\ m$

$\lambda= 1.2828\times10^{-6}$

1 m = 10⁻⁹ nm

$\lambda=1282\ nm$

6 0

3 years ago

On a hot summer day several swimmers decide to jump into a river. They step off the bridge and strike the water at 1.5s later. I

Lilit [14]

The only equation you need is the Δy = v₀t + 1/2at², and in this case, v₀t = 0 because the swimmers are starting from rest. Therefore, Δy = 1/2at², and that is 1/2 x (10m/s²) x (1.5)² = 11.25m.
With sigfigs it is 11m.

6 0

3 years ago