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Alinara [238K]
4 years ago
11

What did physicist James Joule's famous paddle wheel experiment demonstrate?

Physics
2 answers:
Vinvika [58]4 years ago
8 0

Answer:

that the initial gravitational potential energy of the masses transformed into kinetic energy of the paddles and then to thermal energy in the water

Explanation:

Joule was one of the foremost scientists to opine that one form of energy could be converted into other forms. In the famous "paddle wheel" experiment he used a falling weight to pull a string that turned a paddle wheel submerged in a bucket of water. It was discovered that the mechanical energy released by the falling weight was converted into heat energy by the paddle wheel. Joule then measured the amount of heat energy absorbed by the water by recording the temperature of the water before and after the paddle wheel began moving . He discovered that the increase in water temperature was directly related to the amount of kinetic energy released.

PilotLPTM [1.2K]4 years ago
7 0

<u>Answer </u>

A. that the initial gravitational potential energy of the masses transformed into kinetic energy of the paddles and then to thermal energy in the water


<u>Explanation</u>

James Joule allowed some water to fall from a height of 1 foot. the water would turn a paddle wheel at the bottom causing a temperature of water to raise.

The height form which the water fell, mass and the temperature of water was measured and used to calculate mechanical equivalent of heat.

From the choices given the best answer is A. that the initial gravitational potential energy of the masses transformed into kinetic energy of the paddles and then to thermal energy in the water.

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3 years ago
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15 points. give me the method.
AveGali [126]

Answer:

\boxed{{160 \:  m(s)}^{ - 1} }

Explanation:

if \:the \:  frequencies \: are \to \\   f_{1} =  640Hz  \\ and \\f_{2}   = 480Hz \:  \\ but \:  \boxed{v = f \gamma }:   f =  \frac{v}{ \gamma } \\ if \:  \gamma_{1}  -  \gamma _{2}  = 1 =  \gamma  \\ f_{1}  - f_{2}  = 640 - 480 = \boxed{ 160Hz} = f \\ v = f \gamma = 160 \times 1 =  \boxed{{160 \:  m(s)}^{ - 1} }

5 0
3 years ago
Find the resistance of a 0.03 m long copper wire with a radius of .005 m (Area of a circle: π r²).
Bas_tet [7]

Answer:

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3 years ago
An automobile of mass 1.46 cross times to the power of blank 10 cubed kg rounds a curve of radius 25.0 m with a velocity of 15.0
Vsevolod [243]

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<u>Explanation:</u>

given that

Mass\ of\ the\ automobile\ m  =1.46\times 10^3 kg\\radius\ of\ the\ curve\ r =25 m\\velocity\ of\ the\ automobile\ v=15m/s\\

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4 0
3 years ago
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Verizon [17]

Answer:

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