Answer:
The angle when it leaves is the same as the angle when it hits.
Explanation:
think of it as a mirror, mirrors show exactly what you display.
Answer:
Explanation:
a )
This type of spectrum is called line emission spectrum . Because it consists of lines . It is emission spectrum because it is due to emission of radiation from a source .
b ) The wavelength of a photon is inversely proportional to its energy . Photon due to transition between n = 1 and n = 3 will have higher energy than
that due to transition between n = 2 and n = 5 . So the later photon ( B) will have greater wavelength or photon due to transition between n = 2 and n = 5 will have greater wavelength .
Answer:
Explanation:
System of forces in balance
ΣFx = 0
ΣFy = 0
∑MA = 0
MA = F*d
Where:
∑MA : Algebraic sum of moments in the the point (A)
MA : moment in the point A ( N*m)
F : Force ( N)
d : Horizontal distance of the force to the point A ( N*m
Forces acting on the beam
T₁ = 620 N : Tension in cable 1 ,at angle of 30° with the vertical on the left
T₂ : Tension in cable 2, at angle of 50.0° with the vertical on the right.
W : Weight of the beam
x-y T₁ and T₂ components
T₁x= 620*sin30° = 310 N
T₁y= 620*cos30° = 536.94 N
T₂x= T₂*sin50°
T₂y= T₂*cos50°
Calculation of the T₂
ΣFx = 0
T₂x-T₁x = 0
T₂x=T₁x
T₂*sin50° = 310 N
T₂ = 310 N /sin50°
T₂ = 404.67 N
Calculation of the W
ΣFy = 0
T₂y+T₁y-W = 0
(404.67) *cos50° + 536.94 = W
W= 260.12+ 536.94
W= 797.06 N
Location of the center of gravity of the beam
∑MA = 0 , point (A) (point where the cable 2 of the right is located on the beam)
T₁y(5)-W(d) = 0
T₁y(5) = W(d)
d = T₁y(5)/W
d = 536.94(5) / 797.06
d = 3.37m
The center of gravity is located at 3.37m measured from the right end of the beam
Answer:
The angle of incidence is greater than the angle of refraction
Explanation:
Refraction occurs when a light wave passes through the boundary between two mediums.
When a ray of light is refracted, it changes speed and direction, according to Snell's Law:
where
:
is the index of refraction of the 1st medium
is the index of refraction of the 2nd medium
is the angle of incidence (the angle between the incident ray and the normal to the boundary)
is the angle of refraction (the angle between the refracted ray and the normal to the boundary)
In this problem, we have a ray of light passing from air into clear plastic. We have:
(index of refraction of air)
approx. (index of refraction in clear plastic)
Snell's Law can be rewritten as
And since 
, we have
And so
Which means that
The angle of incidence is greater than the angle of refraction
Displacement is the distance between the start- and end-points,
no matter what route is followed from start to finish.
If she travels around half of the circle, then her start- and end-points
are the two ends of a diameter, and her displacement is its length.
The length of the diameter is (2 x radius) = 6.84 meters.
