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3 years ago

Please help me, forgot how to do it. 30 points

Mathematics

2 answers:

Helga [31]3 years ago

5 0

Step-by-step explanation:

<h3>(a). 743 → The product is equal to 743</h3>

<h3>(b). 95.9 → The product is less than 107</h3>

<h3>(c) . 656.2 →The product is more than 647</h3>

attashe74 [19]3 years ago

4 0

Answer:

A. The product is equal to 743.

B. The product is less than 107.

C. The product is more than 647.

Step-by-step explanation:

If both sides of the fraction are equal it is equal, if the top is higher it is greater and if the bottom is greater then it is less. Btw I mean greater than the other side of the fraction.

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(a) How many integers from 1 through 1,000 are multiples of 2 or multiples of 9?

DENIUS [597]

Answer:

(a)There are 500 integers from 1 through 1,000 are multiples of 2.

There are 111 integers from 1 through 1,000 are multiples of 9.

(b)0.611

Step-by-step explanation:

Given the set of Integers from 1 through 1000

The least multiple of 2 is 2 and the highest multiple of 2 in the interval is 1000.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 2,4,6,... is an Arithmetic Progression,

where first term, a =2, common difference, d =2

Nth term of an A.P,

$U_n= a+(n-1)d\\1000=2+2(n-1)\\1000=2+2n-2\\1000=2n\\n=500$

There are 500 integers from 1 through 1,000 are multiples of 2.

Similarly,

Given the set of Integers from 1 through 1000

The least multiple of 9 is 9 and the highest multiple of 9 in the interval is 999.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 9,18,27,... is an Arithmetic Progression,

where first term, a =9, common difference, d =9

Nth term of an A.P,

$U_n= a+(n-1)d\\999=9+9(n-1)\\999=9+9n-9\\999=9n\\n=111$

There are 111 integers from 1 through 1,000 are multiples of 9.

(b)Probability that an integer selected at random is a multiple of 2 or a multiple of 9.

There are a total of 1000 numbers between from 1 through 1,000

n(S)=1000

n(Multiples of 2)=500

n(Multiples of 9)=111

Therefore:

$P(\text{Multiples of 9}) \:OR\: P(\text{Multiples of 2})=\frac{111}{1000} + \frac{500}{1000} \\=\frac{611}{1000} \\=0.611$

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3 years ago

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Answer:

read the answer through and collect all the information you can

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3 years ago

if a company sells about 3 of product A for every 2 of product B, how many of each would they sell if a total of 7500 were sold?

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6 0

3 years ago

The width of a rectangle is the length minus 7 units. The area of the

AleksandrR [38]

Answer:

8 units

Step-by-step explanation:

here's your solution

=> let the length of rectangle be X

=> then width = x - 7

=> area = 8units

=>> area = length*width

=> area = x (x-7) = 8

=> x^2 - 7 = 8

=> now, x^2 - 7x - 8 = 0

=> factories the above equation by middle term split

=> x^2 - 7x - 8

=> x^2 - 8x + x - 8

=> take the common

=> x(x - 8) + 1(x - 8)

=> (x + 1) (x - 8)

neglect (x + 1) because this will in negative for X

=> x - 8 = 0

=> x = 8

=>so, x = 8

=>length = 8 units

3 0

3 years ago

True or False The point (-2, -1) is a solution to the inequality – y < 0. True False

EleoNora [17]

Answer:

True

Step-by-step explanation:

Plug in the point:

-2 - (-1) = -2 + 1 = -1 <0.

This is a true statement

8 0

3 years ago