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11111nata11111 [884]
3 years ago
8

Which of the lines below has a negative slope?

Mathematics
1 answer:
Law Incorporation [45]3 years ago
6 0

Answer:

A

Step-by-step explanation:

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The ratio of boys to girls in the ninth grade is 6:5. If there are 185 girls in the class, how many boys are there.
FrozenT [24]
There are 222 boys in the class. You find this by dividing 185 by 5 which gets you 37, so you have to multiply the 6 by 37 to find the amount of boys.
4 0
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How do you solve 6(2/3x-3)>3
VARVARA [1.3K]

Answer:

14>3

Step-by-step explanation:

you would need to turn the 3 in the parenthesis into a fraction which would result in 9/3. 2/3 - 9/3= -7/3      

Multiply the 7/3 by 6 and by what I have always been taught, you only multiply the top of the fraction. This would leave it to be 42/3 which would be known as 14.

So therefore the answer would be 14>3

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3 years ago
I'm confused on my math homework
Taya2010 [7]
What is the home work

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3 years ago
35 : ? = 20 : 24 <br> QUICKLY PLEASE!!
Archy [21]

Answer:

35:42=20:24

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7 0
3 years ago
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According to DeMorgan 's theorem, the complement of W · X + Y · Z is W' + X' · Y' + Z'. Yet both functions are 1 for WXYZ = 1110
sergeinik [125]

Answer:

The parenthesis need to be kept intact while applying the DeMorgan's theorem on the original equation to find the compliment because otherwise it will introduce an error in the answer.

Step-by-step explanation:

According to DeMorgan's Theorem:

(W.X + Y.Z)'

(W.X)' . (Y.Z)'

(W'+X') . (Y' + Z')

Note that it is important to keep the parenthesis intact while applying the DeMorgan's theorem.

For the original function:

(W . X + Y . Z)'

= (1 . 1 + 1 . 0)

= (1 + 0) = 1

For the compliment:

(W' + X') . (Y' + Z')

=(1' + 1') . (1' + 0')

=(0 + 0) . (0 + 1)

=0 . 1 = 0

Both functions are not 1 for the same input if we solve while keeping the parenthesis intact because that allows us to solve the operation inside the parenthesis first and then move on to the operator outside it.

Without the parenthesis the compliment equation looks like this:

W' + X' . Y' + Z'

1' + 1' . 1' + 0'

0 + 0 . 0 + 1

Here, the 'AND' operation will be considered first before the 'OR', resulting in 1 as the final answer.

Therefore, it is important to keep the parenthesis intact while applying DeMorgan's Theorem on the original equation or else it would produce an erroneous result.

3 0
3 years ago
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