(a) The "average value" of a function over an interval [a,b] is defined to be
(1/(b-a)) times the integral of f from the limits x= a to x = b.
Now S = 200(5 - 9/(2+t))
The average value of S during the first year (from t = 0 months to t = 12 months) is then:
(1/12) times the integral of 200(5 - 9/(2+t)) from t = 0 to t = 12
or 200/12 times the integral of (5 - 9/(2+t)) from t= 0 to t = 12
This equals 200/12 * (5t -9ln(2+t))
Evaluating this with the limits t= 0 to t = 12 gives:
708.113 units., which is the average value of S(t) during the first year.
(b). We need to find S'(t), and then equate this with the average value.
Now S'(t) = 1800/(t+2)^2
So you're left with solving 1800/(t+2)^2 = 708.113
<span>I'll leave that to you</span>
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Answer:
it would be 12 righhht?? because if each bunch is 6 and she has 2 bunches you would add 6+6 and get 12!! i thinkkkk or multiply :))
Step-by-step explanation:
Answer:
There are 6,296 children at the carnival
Step-by-step explanation:
The number of each group of people can be expressed as;
Number of boys (b)+number of adults (a)=7,052
b+a=7,052....equation 1
Number of girls (g)=Number of adults (a)-756
g=a-756....equation 2
But Number of girls (g)=number of boys (b)
Replacing the value of b in equation 1 with that of g in equation 2;
(a-756)+a=7,052
a+a=7,052+756
2 a=7,808
a=7,808/2
a=3,904
Replace the value of a in equation 2 with 3,904
g=3,904-756
g=3,148
But since g=b
g=b=3,148
b=3,148
Total number of children=Total number of boys (b)+total number of girls (g)
Total number of children=b+g
where;
b=3,148
g=3,148
replacing;
Total number of children=(3,148+3,148)=6,296
There are 6,296 children at the carnival
Answer:
See below.
Step-by-step explanation:
You don't provide the original side length, but since the scale factor is greater than 1, all correct answers are lengths that are greater than the original side length.
Answer: choose any two numbers that are greater than the original length.
