Answer:
Equation: 
Asymptotes: 
Step-by-step explanation:
Given
Let the reciprocal function be:

First, it was reflected across the x-axis.
The rule is: (x,-y)
So, we have:

Next, translated 5 units right.
The rule is: (x,y)=>(x-5,y)
So:

Lastly, translated 7 units down.
The rule is: (x,y) => (x,y-7)
So:

To get the vertical asymptote, we simply equate the denominator to 0.
i.e.


To get the horizontal asymptote, we simply equate y to the constant.
i.e.

