3 years ago

3(k+9)=8-(-3k-19) solution types

2 answers:

disa [49]3 years ago

6 0

Hello! your answer would be infinite solutions, or b! hope this helped! ;)

5 0

Answer:

Step-by-step explanation

3(k+9)=8-(-3k-19)

=> 3k+27=8+3k+19

=>3k+27-8-3k-19=0

=>0=0

so with all value of k, 3(k+9)=8-(-3k-19) always

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