Answer:
9x + 4y < 110
Step-by-step explanation:
This inequality works because its the cost of hammers ($9) multiplied by how many hammers are bought (x) plus the cost of wrenches ($4) multiplied by how many wrenches are bought (y). The total cost has to be less than 110.
Answer:
73.90%
Step-by-step explanation:
Let Event D=Defective, D' = Non Defective
Let Event N=New Machine, N' = Old Machine
From the given information:
![P(D|N')=0.25\\P(D|N)=0.09\\P(N)=0.7\\P(N')=0.3](https://tex.z-dn.net/?f=P%28D%7CN%27%29%3D0.25%5C%5CP%28D%7CN%29%3D0.09%5C%5CP%28N%29%3D0.7%5C%5CP%28N%27%29%3D0.3)
We are required to calculate the probability that a widget was manufactured by the new machine given that it is non defective.
i.e. ![P(N|D')](https://tex.z-dn.net/?f=P%28N%7CD%27%29)
![P(D'|N')=1-P(D|N')=1-0.25=0.75\\P(D'|N)=1-P(D|N)=1-0.09=0.91](https://tex.z-dn.net/?f=P%28D%27%7CN%27%29%3D1-P%28D%7CN%27%29%3D1-0.25%3D0.75%5C%5CP%28D%27%7CN%29%3D1-P%28D%7CN%29%3D1-0.09%3D0.91)
Using Baye's Law of conditional Probability
![P(N|D')=\dfrac{P(D'|N)P(N)}{P(D'|N)P(N)+P(D'|N')P(N')} \\=\dfrac{0.91*0.7}{0.91*0.7+0.75*0.3}\\ =0.73897\\\approx 0.7390](https://tex.z-dn.net/?f=P%28N%7CD%27%29%3D%5Cdfrac%7BP%28D%27%7CN%29P%28N%29%7D%7BP%28D%27%7CN%29P%28N%29%2BP%28D%27%7CN%27%29P%28N%27%29%7D%20%5C%5C%3D%5Cdfrac%7B0.91%2A0.7%7D%7B0.91%2A0.7%2B0.75%2A0.3%7D%5C%5C%20%3D0.73897%5C%5C%5Capprox%200.7390)
Therefore given that a selected widget is non-defective, the probability that it was manufactured by the new machine is 73.9%.
it should be B
if i’m wrong please correct me
28 oz for $4.20. Hope this helps :)