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Fynjy0 [20]
3 years ago
5

Would u rather/ enjoy now suffer later or suffer now enjoy later

Physics
1 answer:
Oliga [24]3 years ago
3 0

Answer:

Suffer later

Explanation:

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Position update: Initially the bottom of the block is at y = 0.12 m. Approximating the average velocity in the first time interv
aleksklad [387]

Answer:

The new position is 0.1865 m

Explanation:

As the context of the data is not available, thus following data is utilized from the question as attached above

x_relax=0.32 m

x_stiff=0.13 m

spring stiffness k=9 N/m

mass of block =0.073 kg

t=0.07 s

Velocity of the block is to be estimated thus

Force due to compression in spring is given as

F_s=k Δx

F_s=9(0.32-0.13)

F_s=1.71 N

Force on the block is given as

F_m=mg

F_m=0.073 x 9.8

F_m=0.71 N

Net Force

F=F_s-F_m

F=1.71-0.71 N

F=1 N

As Ft=Δp

So

Δp=1x0.07=0.07 kgm/s

Δp=p_final-p_initial

0.07=p_final-0

p_final=0.07 kgm/s

p_final=m*v_f

v_f=(p_final)/(m)

v_f=0.07/0.073

v_f=0.95 m/s

So now the velocity of the block is 0.95 m/s

time is 0.07 s

y_new=y_initial+y_travel

y_new=0.12+(0.95 x 0.07)

y_new=0.12+0.065

y_new=0.1865 m

So the new position is 0.1865 m

4 0
3 years ago
A ruler of length 0.30m is pivoted at its centre. Equal and opposite forces of magnitude 2.0N are applied to the ends of the rul
kow [346]

Answer:

0.3858 Nm

Explanation:

The torque of the couple is the dot product of the force vector and the couple vector from 1 end of the ruler to the center. This equals to the product of their magnitude times the cosine() of the angle made by their direction:

T = \vec{F} \cdot \vec{s} = Fscos(50^0) = 2 * 0.3 * 0.643 = 0.3858 Nm

6 0
3 years ago
Two cars approach each other; both cars are moving westward, one at 85 km/h, the other at 54 km/h. what is the magnitude of the
Anna007 [38]
Good afternoon.

In the reference of the second car, itself is stopped! It is the same thing as adding the opposite speed vector of this car to the rest of the world. See below:

Begginning:

    Car 1                  Car 2 
 → 85 km/h              → 54 km

Going to the referential of car 2, adding ← 54 km/h to both cars:


New Reference:

Car 1                                      Car 2
(→85 km/h) + (←54 km/h)       (→ 54 km/h) + (← 54 km/h)

Car 1                     Car 2
→ 31 km/h               0 km/h


So, relative to car 2, car 1 has a velocity of<em> 31 km/h</em>
4 0
3 years ago
football game customarily begins with a coin toss to determine who kicks off. The referee tosses the coin up with an initial spe
LuckyWell [14K]

Answer:

1.28 m

Explanation:

You are given the initial speed that is 5 m/s. Since the coin is sent upwards, this means that the speed is positive according to the co-ordinate system in the y axis. Additionally, there is the gravity that curbs the coin in the opposite direction making the final speed becomes zero at the highest point, so the gravity takes negative sign.

So, from the explanation we have:

Vo = 5 m/s

V = 0 m/s

a = -9.8 m/s^2

so, we use the following equation to find y (hight)

V^2 = Vo^2 + 2ay

y = V^2 - Vo^2 / 2a

y = (0 m/s)^2 - (5 m/s)^2 / 2*(-9.8 m/s^2)

y = - (25 m^2 / s^2) / -19.6 m /s^2

y = 1.28 m

3 0
3 years ago
In this experiment, the blank
lesya [120]

Answer:

the dependent variable is the one that changes because the independent variable was changed. The dependent isn't intentionally manipulated

Explanation:

3 0
3 years ago
Read 2 more answers
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