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Fynjy0 [20]
3 years ago
5

Would u rather/ enjoy now suffer later or suffer now enjoy later

Physics
1 answer:
Oliga [24]3 years ago
3 0

Answer:

Suffer later

Explanation:

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3. A large passenger ship required a force of 1,600,000 N to move 2000 m. How much work is done on the ship?​
Dovator [93]

Answer:

3,200,000,000 J

Explanation:

Work is defined as the amount of energy transferred as an object is moved a certain distance with a certain force. Mathematically, we express this with the equation

W=Fs

where W is work (measured in joules), F is the force applied (in Newtons), and s is the distance, also called the <em>displacement </em>(in meters).

Here, we have F = 1,600,000 N and s = 2000 m, so our work will be

W=1.600.000(2.000)=3.200.000.000 J

7 0
3 years ago
Kenitic Energy (KE)<br> 1.doubled
astra-53 [7]

Answer:

mass

Explanation:

This energy of motion is what we call kinetic energy. ... In fact, kinetic energy is directly proportional to mass: if you double the mass, then you double the kinetic energy. Second, the faster something is moving, the greater the force it is capable of exerting and the greater energy it possesses.

pls make as brainlieast

3 0
3 years ago
With no effort at all, you'll have deep and lasting relationships.<br> True<br> False
Firdavs [7]
The correct answer is false
7 0
3 years ago
What force is required to accelerate a body with a mass of 15 kilograms at a rate of 8 m/s²?
Dominik [7]
Force is defined as Mass multiplied by Acceleration, or F = MA.
We have our mass, 15 kg.
We also have our acceleration, 8 m/s^2.
Let's plug in our numbers and solve.

F = 15(8)
Multiply 8 by 15.
8 • 15 = 120.

Your Force is 120.
Remember, the unit of measure for Force is Newtons (N).

Your final answer is:

120N.

I hope this helps!
7 0
3 years ago
a rock is vertically upward with a velocity of 10 m/s. calculate the maximum height it reaches and time taken to reach that heig
lina2011 [118]

Answer:

maximum height: p(t) = Vo * t - 1/2 * g * t^2

p’(t) = v(t) = 0 = Vo - g*t. So, maximum height occurs when t = Vo / g

p(Vo / g) = Vo^2/g - 1/2 * g * (Vo/g)^2

Vo = 10 m / s. Let’s approximate g = 10 m / s^2

p(Vo / g) = 10^2 / 10 - 1/2 * 10 * (10/10)^2 = 10 - 5 = 5 meters (approximately)

Calculation of time:

v = u + gt

0 = 10√2 + (-10)t

-10√2 = -10t

2 = √2s

8 0
3 years ago
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