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Fynjy0 [20]
3 years ago
5

Would u rather/ enjoy now suffer later or suffer now enjoy later

Physics
1 answer:
Oliga [24]3 years ago
3 0

Answer:

Suffer later

Explanation:

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Batman, whose mass is 89.5 kg, is holding on to the free end of a 13.4 m rope, the other end of which is fixed to a tree limb ab
astra-53 [7]

Answer:

8.2\times 10^{3} J

Explanation:

L = length of the rope connected = 13.4 m

\theta = Angle made by the rope with the vertical = 72.4°

h = height gained by the batman above the reference point  

Height gained by the batman above the reference point  is given as

h = L(1 - Cos\theta )

m = mass of batman = 89.5 kg

g = acceleration due to gravity = 9.8 ms⁻²

Work done against gravity is same as the gravitational potential energy gained by batman and is given as

W = mgh

W = mgL(1 - Cos\theta )

Inserting the above values

W = (89.5)(9.8)(13.4)(1 - Cos72.4 )

W = 8.2\times 10^{3} J

3 0
3 years ago
A 2.1-mF capacitor is discharged through a 4.0-kΩ resistor. How long will it take for the capacitor to lose half its initial sto
Harrizon [31]

Answer:

the answer is a)5.82s

Explanation:

Hello!

The first thing we must understand to solve this exercise is that a capacitor has the following characteristic function

V=(Vo)e^{-t/RC}

where

Vo=initial voltage

V=voltage in an instant of time

t=time

R=resistance=4000Ω

C=capacitance=2.1-mF=0.0021F

we must consider that the final voltage is half of the initial voltage so we deduce the following equation

V=Vo/2

Now we replace in the initial equation, and start an algebraic process to find t

\frac{Vo}{2} =(Vo)e^{-t/RC}\\0.5=e^{-t/RC}\\ln(0.5)=ln(e^{-t/RC})\\ln(0.5)=\frac{-t}{RC} \\t=-(RC)ln0.5

finally with the equation ready, we use the resistance and capacitance values ​​to find the time value

t=-(4000)(0.0021)ln(0.5)=5.82s

the answer is a)5.82s

4 0
3 years ago
What are the rarefaction and compression regions of a guitar string
andrezito [222]

Answer:

The middle and end of the string respectively

Explanation:

Rarefaction means region of maximum displacement and compression means region of minimum displacement, hence.

We expect a maximum displacement at the middle of the string because it is said to vibrate greatest at this point and conversely vibrate least at the end point which is the region of compression.

3 0
3 years ago
Which statement best describes what Kendall can measure?
Vaselesa [24]

Answer + Explanation:

B

She can measure the volume and mass of the marble, the volume and mass of the water, and the mass of the graduated cylinder.




Hope This Helped :D

6 0
2 years ago
1. A truck with a mass of 8, 000 kg is traveling at 26.8 m/s when it hits the brakes. A.)What is the momentum of the truck befor
NikAS [45]

Answer:

1. A.) The moment of the truck before it hits the brakes is 214,400 kg·m/s

B.) The force it takes to stop the truck is approximately 17,290.4 N

Explanation:

1. A.) The given parameters are;

The mass of the truck, m = 8,000 kg

The velocity of the truck when it hits the brakes, u = 26.8 m/s

Momentum = Mass × Velocity

The moment of the truck = The mass of the truck × The velocity of the truck

Therefore;

The moment of the truck before it hits the brakes = 8,000 kg × 26.8 m/s = 214,400 kg·m/s

B.) The amount of momentum lost when the truck comes to a stop = The initial momentum of the truck

The time it takes the truck to come to a complete stop, t = 12.4 s

The deceleration, "a" of the truck is given by the following kinematic equation of motion

v = u - a·t

Where;

v = The final velocity of the truck = 0 m/s

u = The initial velocity = 26.8 m/s

a = the deceleration of the truck

t = The time of deceleration of the truck = 12.4 s

Substituting the known values gives;

0 = 26.8 - a × 12.4

Therefore;

26.8 = a × 12.4

a = 26.8/12.4 ≈ 2.1613

The deceleration (negative acceleration) of the truck, a ≈ 2.1613 m/s²

Force = Mass × Acceleration

The force required to stop the truck = The mass pf the truck × The deceleration (negative acceleration) given to the truck

∴ The force it takes to stop the truck = 8,000 kg × 2.1613 m/s² ≈ 17,290.4 N.

8 0
3 years ago
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