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Lesechka [4]
3 years ago
11

The distance between two objects is increased by three times the oringinal distance. How will this change the force of attractio

n between two objects
Physics
1 answer:
tigry1 [53]3 years ago
8 0
<span>The distance between two objects is increased by three times the oringinal distance.  Since they were already separated by one time the original distance,
the additional three times the oringinal distance now puts them four times the original distance apart.

Whether we're talking about the gravitational forces of attraction or
the electrical forces of attraction, either one is inversely proportional
to the square of the distance between the objects. 

So changing the distance to four times the original distance causes
the forces to become 1/4</span>² as strong as they were originally. 

The forces become 1/16 of their original magnitude.<span>
 </span>
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What is the wavelength (in nm) of a photon emitted during transition from the n = 3 state to the n = 1 state in the H atom?
Mkey [24]

Answer:

\lambda=103\ nm

Explanation:

E_n=-2.179\times 10^{-18}\times \frac{1}{n^2}\ Joules

For transitions:

Energy\ Difference,\ \Delta E= E_f-E_i =-2.179\times 10^{-18}(\frac{1}{n_f^2}-\frac{1}{n_i^2})\ J=2.179\times 10^{-18}(\frac{1}{n_i^2} - \dfrac{1}{n_f^2})\ J

\Delta E=2.179\times 10^{-18}(\frac{1}{n_i^2} - \dfrac{1}{n_f^2})\ J

Also, \Delta E=\frac {h\times c}{\lambda}

Where,  

h is Plank's constant having value 6.626\times 10^{-34}\ Js

c is the speed of light having value 3\times 10^8\ m/s

So,  

\frac {h\times c}{\lambda}=2.179\times 10^{-18}(|\frac{1}{n_i^2} - \dfrac{1}{n_f^2}|)\ J

\lambda=\frac {6.626\times 10^{-34}\times 3\times 10^8}{{2.179\times 10^{-18}}\times (|\frac{1}{n_i^2} - \dfrac{1}{n_f^2}|)}\ m

So,  

\lambda=\frac {6.626\times 10^{-34}\times 3\times 10^8}{{2.179\times 10^{-18}}\times (|\frac{1}{n_i^2} - \dfrac{1}{n_f^2}|)}\ m

Given, n_i=3\ and\ n_f=1

\lambda=\frac{6.626\times 10^{-34}\times 3\times 10^8}{{2.179\times 10^{-18}}\times |(\frac{1}{3^2} - \dfrac{1}{1^2})}|\ m

\lambda=\frac{10^{-26}\times \:19.878}{10^{-18}\times \:2.179|\left(\frac{1}{9}-\frac{1}{1}\right)|}\ m

\lambda=1.03\times 10^{-7}\ m

1 m = 10⁻⁹ nm

\lambda=103\ nm

4 0
3 years ago
This diagram shows the process that powers stars. This process is called?
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4 0
2 years ago
Read 2 more answers
An ac generator with peak voltage 100 volts is placed across a 10-? resistor. What is the average power dissipated?
Romashka [77]
The correct answer is: Average Power  = 500 W

Explanation:
Root-mean square voltage = Vrms = Vpeak /√2 = 100 / √2 volts
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3 0
3 years ago
If Scoobie could drive a Jetson's flying car at a constant speed of 450.0 km/hr across oceans and space, approximately how long
vladimir2022 [97]

Answer:

The value is t = 3.6 \  days

Explanation:

From the question we are told that

The speed is v  =  450.0 km/h

The radius of the earth is R =  6200 \  km

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C =  2\pi  R

=> C =   2 * 3.142 *   6200

=> C =  38960.8 \ km

Generally the time taken is mathematically represented as

t =  \frac{38960.8}{450.0}

         t = 86.6 \  hr

Converting to days

         t = \frac{86.6}{24}

=>       t = 3.6 \  days

7 0
2 years ago
Electromagnetic radiation that has a short wavelength will have a ________ frequency.
ArbitrLikvidat [17]
High frequency , it is because wavelength is inversely proportional to frequency
8 0
3 years ago
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