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Lesechka [4]
3 years ago
11

The distance between two objects is increased by three times the oringinal distance. How will this change the force of attractio

n between two objects
Physics
1 answer:
tigry1 [53]3 years ago
8 0
<span>The distance between two objects is increased by three times the oringinal distance.  Since they were already separated by one time the original distance,
the additional three times the oringinal distance now puts them four times the original distance apart.

Whether we're talking about the gravitational forces of attraction or
the electrical forces of attraction, either one is inversely proportional
to the square of the distance between the objects. 

So changing the distance to four times the original distance causes
the forces to become 1/4</span>² as strong as they were originally. 

The forces become 1/16 of their original magnitude.<span>
 </span>
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)If a force of 5.00 N is needed to open a 90.0 cm wide door when applied at the edge opposite the hinges, what force must be app
masha68 [24]

Answer:

A force of 12.857 newtons must be applied to open the door.

Explanation:

In this case, a force is exerted on the door, a moment is performed and the door is opened. If moment remains constant, the force is inversely proportional to distance respect to axis of rotation passing through hinges. That is:

F \propto \frac{1}{r}

F = \frac{k}{r} (Eq. 1)

Where:

F - Force, measured in newtons.

k - Proportionality ratio, measured in newton-meters.

r - Distance respect to axis of rotation passing through hinges, measured in meters.

From (Eq. 1) we get the following relationship and clear the final force within:

F_{A}\cdot r_{A} = F_{B}\cdot r_{B}

F_{B}=\left(\frac{r_{A}}{r_{B}} \right)\cdot F_{A}(Eq. 2)

Where:

F_{A}, F_{B} - Initial and final forces, measured in newtons.

r_{A}, r_{B} - Initial and final distances, measured in meters.

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F_{B}= \left(\frac{0.9\,m}{0.35\,m} \right)\cdot (5\,N)

F_{B} = 12.857\,N

A force of 12.857 newtons must be applied to open the door.

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3 years ago
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From the question we have

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We have the final answer as

<h3>0.5 m/s²</h3>

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