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3 years ago

Help a nga out with his physic hw

Physics

1 answer:

aleksandr82 [10.1K]3 years ago

7 0

Rarefactions are where you see the wave further apart. Where it's closer together, it's called a compression.

You might be interested in

Name two types of sound wave

kiruha [24]

Explanation:

two types of sound wave

transverse wave
Longitudinal wave

5 0

3 years ago

What is the acceleration due to gravity at an altitude of 116?

Schach [20]

Gravitational acceleration (Ga) is inversely proportional to k / Distance^2

so Ga * Distance^2 = K

On the surface of Earth acceleration due to gravity is about 9.8m/s^2 with an average distance to the earths core of about 6371 km (Wolfram alpha).

So k = 9.8 * 6371^2
I'm presuming that your distance of 116 is km

As
Ga = k / distance^2

Ga = ((9.8 * 6371^2) / (6371 + 116)^2 ) = 397778481.8 / 42081169

= 9.45 m/s^2 to 2sf

7 0

4 years ago

Before collecting a specimen of urine or feces, the nursing assistant asks the nurse or consults the lab for?

bulgar [2K]

Before collecting a specimen of urine or feces, the nursing assistant asks the nurse or consults the lab for which storage and delivery method to use.

There are different tests that need to be performed on a urine or feces specimen. It depends on the patients that which test would be asked for him to be done.

The storage and delivery methods for urine and feces in the case of different tests has to be consulted by the nurse or consultant.

Incase of an emergency test, whose results are immediately required the method of delivery is a fast mode one. For patients that have a mild disease or are not at risk, other reliable methods can be used. Each specimen should be properly labeled for proper checking.

To learn more about urine specimen, click here:

brainly.com/question/28329488

#SPJ4

8 0

2 years ago

Did the displacement at this point reach its maximum of 2 mm before or after the interval of time when the displacement was a co

Igoryamba

Answer:

a. before

Explanation:

Did the displacement at this point reach its maximum of 2 mm before or after the interval of time when the displacement was a constant 1 mm?

from the graph given from a source. the vertical axis represents the displacement of the graph motion, whilst the horizontal side is representing the time variable of the motion .

displacement is distance in a specific direction.

before the displacement was maximum at 2mm was instant at time=0.04s.

But later was constant at 0.06s at a displacement point of 1mm

4 0

3 years ago

Two charged particles, q1 and q2, are located on the x-axis, with q1 at the origin and q2 initially atx1 = 14.7 mm.In this confi

Sladkaya [172]

Answer:

The force magnitude is 1.75 μN acting outward from the origin towards x₂

Explanation:

The given parameters, are;

The location of q₁ = The origin

The location of q₂ = 14.7 mm from q₁

The repulsive force exerted on q₂ by q₁ = 2.62 μN

The location the particle q₂ is located to = 18.0 mm from q₁

By Coulomb's law, we have;

$F = k\dfrac{q_1 \times q_2 }{r^2}$

Where;

k = Coulomb constant ≈ 8.99 × 10⁹ kg·m³/(s²·C²)

r = The distance between the particles

F = The force acting between the particles

When r = 14.7 mm F = 2.62 μN

∴ q₂ × q₁ = r² × F/k = (14.7×10^(-3))²×2.62×10^(-6)/(8.9875517923^9) ≈ 1.48 × 10⁻¹⁸

q₂ × q₁ = 1.48 × 10⁻¹⁸ C²

When the distance is increased to 18.0 mm, we have;

F = (8.9875517923^9) × 1.4796647 × 10^(-18)/((18×10^(-3))²) = 1.75 × 10⁻⁶ N

∴ F = 1.75 μN.

Therefore;

The force magnitude is 1.75 μN outward from the origin towards x₂.

8 0

4 years ago