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3 years ago

12

Calculate the total resistance in a parallel circuit made up of resistances of 2, 3, and 4.

1 answer:

Tamiku [17]3 years ago

5 0

Answer:

<em><u>0</u></em><em><u>.</u></em><em><u>9</u></em><em><u>1</u></em>

Explanation:

as equivalence resistance can be found out using the

1/Req = 1/r1 +1/r2 +1/r3......

now, 1/req= 1/2+1/3+1/4

=6/12+4/12+3/12

=13/12

i.e, req =12/13 =0.91

✌️:)

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A 0.5 m diameter wagon wheel consists of a thin rim having a mass of 7 kg and six spokes, each with a mass of 1.2 kg. 1.2 kg 7 k

Arte-miy333 [17]

Explanation:

It is given that,

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$I=I_1+I_2$

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3 years ago

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Given

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$11=\sqrt{\frac{2GM}{R}}$ --------------------1

If Escape velocity is three times and the radius is also the three times

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$V_e_2=\sqrt{\frac{2GM}{R}}=V_e$

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3 years ago

A 90 kg man stands in a very strong wind moving at 17 m/s at torso height. As you know, he will need to lean in to the wind, and

victus00 [196]

Answer:

a) $t=195.948N.m$

b) $\phi=13.6 \textdegree$

Explanation:

From the question we are told that:

Density $\rho=1.225kg/m^2$

Velocity of wind $v=14m/s$

Dimension of rectangle:50 cm wide and 90 cm

Drag coefficient $\mu=2.05$

a)

Generally the equation for Force is mathematically given by

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b)

Generally the equation for torque due to weight is mathematically given by

$t=d*Mg*sin90$

Where

$d=sin \phi$

Therefore

$t=sin \phi*Mg*sin90$

$195.948=833sin \phi$

$\phi=sin^{-1}\frac{195.948}{833}$

$\phi=13.6 \textdegree$

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3 years ago