3 years ago

Calculate the total resistance in a parallel circuit made up of resistances of 2, 3, and 4.

Physics

1 answer:

Tamiku [17]3 years ago

5 0

Answer:

0.91

Explanation:

as equivalence resistance can be found out using the

1/Req = 1/r1 +1/r2 +1/r3......

now, 1/req= 1/2+1/3+1/4

=6/12+4/12+3/12

=13/12

i.e, req =12/13 =0.91

✌️:)

You might be interested in

I need help with this

Kamila [148]

A. corn syrup sorry if I replied late

3 0

3 years ago

Read 2 more answers

Use each of the following terms in a separate

Alenkinab [10]

I think the correct answer is going to be A

3 0

3 years ago

A car drives 100 km north, 50 km east, then 10 km south. What is the car's displavement?

Over [174]

Answer:

$\sqrt{ ({40}^{2} } + {50}^{2} ) = \sqrt{(1600 + 2500)} = \sqrt{4100} = 64.03$

6 0

4 years ago

An iron ball is dropped at a height of 10 m from the surface of the moon.

galben [10]

Answer:

3.51s

Explanation:

There are many students who can not get answers step by step and on time

So there are a wats up group where you can get help step by step and well explained by the trusted experts.

3 0

3 years ago

If the area of an iron rod is 10 cm by 0.5 cm and length is 35 cm. Find the value of resistance, if 11x10^-8 ohm.m be the resist

malfutka [58]

Answer:

Resistance of the iron rod, R = 0.000077 ohms

Explanation:

It is given that,

Area of iron rod, $A=10\ cm\times 0.5\ cm=5\ cm^2 = 0.0005\ m^2$

Length of the rod, L = 35 cm = 0.35 m

Resistivity of Iron, $\rho=11\times 10^{-8}\ \Omega-m$

We need to find the resistance of the iron rod. It is given by :

$R=\rho\dfrac{L}{A}$

$R=11\times 10^{-8}\times \dfrac{0.35\ m}{0.0005\ m^2}$

$R=0.000077 \Omega$

So, the resistance of the rod is 0.000077 ohms. Hence, this is the required solution.

6 0

3 years ago