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3 years ago

How do objects at rest and in motion respond in the presence of an external, unbalanced force?

Physics

1 answer:

koban [17]3 years ago

5 0

Explanation:

Objects at rest and in motion respond to the presence of an external unbalanced force by simple changing their magnitude of motion or position.

We have this knowledge from Newtons first law of motion "a body will remain in a state of rest or continue with uniform motion unless if it is acted upon by an external force".

When an external force acts on a body at rest, it will change the position of the body or set it motion.
For a body in motion, an external force can make they come to rest or change the motion of the body

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How much kinetic energy a spring that streches 4m would be?

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Answer:

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What can you infer from the fact that although CFC's have been banned, refrigerators and aerosol cans are still being sold?

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3 years ago

Read 2 more answers

A skydiver of 75 kg mass has a terminal velocity of 60 m/s. At what speed is the resistive force on the skydiver half that when

ankoles [38]

Answer:

The speed of the resistive force is 42.426 m/s

Explanation:

Given;

mass of skydiver, m = 75 kg

terminal velocity, $V_T = 60 \ m/s$

The resistive force on the skydiver is known as drag force.

Drag force is directly proportional to square of terminal velocity.

$F_D = kV_T^2$

Where;

k is a constant

$k = \frac{F_D_1}{V_{T1}^2} = \frac{F_D_2}{V_{T2}^2}$

When the new drag force is half of the original drag force;

$F_D_2 = \frac{F_D_1}{2} \\\\\frac{F_D_1}{V_{T1}^2} = \frac{F_D_2}{V_{T2}^2} \\\\\frac{F_D_1}{V_{T1}^2} = \frac{F_D_1}{2V_{T2}^2} \\\\\frac{1}{V_{T1}^2} = \frac{1}{2V_{T2}^2}\\\\2V_{T2}^2 = V_{T1}^2\\\\V_{T2}^2= \frac{V_{T1}^2}{2} \\\\V_{T2}= \sqrt{\frac{V_{T1}^2}{2} } \\\\V_{T2}= \frac{V_{T1}}{\sqrt{2} } \\\\V_{T2}= 0.7071(V_{T1})\\\\V_{T2}= 0.7071(60 \ m/s)\\\\V_{T2}= 42.426 \ m/s$

Therefore, the speed of the resistive force is 42.426 m/s

8 0

3 years ago

The pupil of an eagle’s eye has a diameter of 6.0 mm. Two field mice are separated by 0.010 m. From a distance of 185 m, the eag

max2010maxim [7]

Answer:

time is 5.973826 sec

Explanation:

Given data

diameter D = 6.0 mm 6× $10^{-3}$ m

separated d = 0.010 m

distance (dis) 185 m

speed s = 16 m/s

wavelength = 550 nm = 550 $10^{-9}$ m

to find out

How much time passes

solution

we know that for resolution we use Rayleigh's Criterion i.e

θ = 1.22 wavelength / diameter = separated / distance 1

we calculate distance 1 by put value wavelength, diameter and separated

distance 1 = diameter × separated / 1.22 wavelength

distance 1 = 6× $10^{-3}$ × 0.010 / 1.22 × 550 × $10^{-9}$

distance 1 = 89.418778

so time will be i.e = distance (dis) - distance 1 / speed

time = ( 185 - 89.418778) / 16

time = 5.973826 sec

time is 5.973826 sec

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3 years ago

describe how a physical property, such as mass or texture, can change without causing a change in the substance

kari74 [83]

On the mass subject you could simply change the weight, on the texture subject you could smooth it out like polishing fresh wood, or you could change the color of water with a drink-mix packet. Hope it helped!

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3 years ago