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3 years ago

An engine raises 120kg of water through a height of 40m in 30s.What is the power of the engine take gravity to be = 10m/s.

Physics

1 answer:

alexgriva [62]3 years ago

3 0

Answer:

1600 W

Explanation:

Power is the product of force and distance, divided by time.

P = (120 kg)(10 m/s²)(40 m)/(30 s) = 1600 kg·m²/s³ = 1600 W

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A car with a mass of 880 kg is moving on the road with constant velocity. The force exerted by engine is 1600N. What is the fric

vovangra [49]

Answer:

1600 N

Explanation:

F-F' = ma.................. Equation 1

Where F = Force exerted by the engine, F' = Frictional Force, m = mass of the car, a = acceleration of the car.

make F' the subject of the equation

F' = F-ma............... Equation 2

Given: F = 1600 N, m = 880 kg, a = 0 m/s (moving with a constant velocity).

Substitite these values into equation 2

F' = 1600+880(0)

F' = 1600 N.

4 0

3 years ago

A parallel-plate capacitor with plates of area 360 cm2 is charged to a potential difference V and is then disconnected from the

Softa [21]

Answer:

$Q=3.9825\times 10^{-9} C$

Explanation:

We are given that a parallel- plate capacitor is charged to a potential difference V and then disconnected from the voltage source.

1 m =100 cm

Surface area =S= $\frac{360}{10000}=0.036 m^2$

$\Delta d=0.8 cm=0.008 m$

$\Delta V=100 V$

We have to find the charge Q on the positive plates of the capacitor.

V=Initial voltage between plates

d=Initial distance between plates

Initial Capacitance of capacitor

$C=\frac{\epsilon_0 S}{d}$

Capacitance of capacitor after moving plates

$C_1=\frac{\epsilon_0 S}{(d+\Delta d)}$

$V=\frac{Q}{C}$

Potential difference between plates after moving

$V=\frac{Q}{C_1}$

$V+\Delta V=\frac{Q}{C_1}$

$\frac{Qd}{\epsilon_0S}+100=\frac{Q(d+\Delta d)}{\epsilon_0S}$

$\frac{Q(d+\Delta d)}{\epsilon_0 S}-\frac{Qd}{\epsilon_0S}=100$

$\frac{Q\Delta d}{\epsilon_0 S}=100$

$\epsilon_0=8.85\times 10^{-12}$

$Q=\frac{100\times 8.85\times 10^{-12}\times 0.036}{0.008}$

$Q=3.9825\times 10^{-9} C$

Hence, the charge on positive plate of capacitor= $Q=3.9825\times 10^{-9} C$

6 0

4 years ago

entrained air is drier than the air within a cloud. considering the phase change of water, how could this lead to further coolin

Wittaler [7]

Dry air adjacent to the cloud is entrained air is drier than the air within a cloud. The evaporation occurs in the cloud which cools the air. The cooling of air increases its density and creates a downdraft.

<h3>How clouds are formed?</h3>

A cloud can be described as a mass of ice crystals or water drops suspended in the atmosphere. Clouds can be formed when the water condenses in the atmosphere. The sky possesses some quantity of water vapours and it is invisible to us.

Clouds can be formed when an area of air gets cooler until the water vapour there condenses to liquid form. At this point, the air gets saturated with water vapours.

A cloud can never be perfectly adiabatic. Therefore, after mixing the environmental air with the clouds, its boundaries will not stay well defined and this process is called entrainment.

Learn more about cloud formation, here:

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5 0

1 year ago

If the length of a ramp (an inclined plane) is 12 ft, and it rises 2 ft, what is its MA?

dangina [55]

The MA is 6! Hope This Helps!

3 0

3 years ago

Help guys <br><br> Jehdjdbdbxzjjxxjixhwvwbsbsbs

Andrew [12]

Answer:

<em>12.5watts</em>

Explanation:

Power = Workdone/Time

Since workdone = Force * Distance

Power = Force *distance/Time

Given

Force = 150N

Distance = 10m

Time = 2 minutes = 120seconds

Required

Power

Substitute the given values into the formula;

Power = 150 * 10/120

Power = 1500/120

Power = 12.5Watts

Hence his power is 12.5watts

6 0

4 years ago

An engine raises 120kg of water through a height of 40m in 30s.What is the power of the engine take gravity to be = 10m/s.​

An engine raises 120kg of water through a height of 40m in 30s.What is the power of the engine take gravity to be = 10m/s.