<u>Define x:</u>
Let one of the numbers be x.
The other number is x + 2
<u>Construct equation:</u>
<span>twice the smaller is 16 more than the larger
</span>⇒2x = x + 2 - 16
<u>Solve x:</u>
2x = x + 2 - 16
x = -14
<u>Find the two numbers:</u>
Smaller number = x = -14
Larger number = x + 2 = -12
Answer: The two numbers are -14 and -12
<h3>
Answer: 2p + 3q</h3>
Work Shown:
log(200) = log(2^3*5^2)
log(200) = log(2^3) + log(5^2)
log(200) = 3*log(2) + 2*log(5)
log(200) = 3*q + 2*p
log(200) = 2p + 3q
The log rules I used were
log(A*B) = log(A)+log(B)
log(A^B) = B*log(A)
Answer:
x=16
y=-6
Step-by-step explanation:
Answer:they are the same shape but not necessarily same size they are not congruent bc that require them to be the same size which they're not unless the scale factor is
1.0
Step-by-step explanation:
Using cosine law,
d^2 = 65^2 + 35^2 - 2(65)(35)cos140
= 8935.5022
d = sqrt(8935.5022)
= 94.5 m
Angle = inverseCos(35sin40 / 94.5) = 76.23 degrees South of East
