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podryga [215]
3 years ago
9

How can you use remainders in divison problems

Mathematics
2 answers:
iren [92.7K]3 years ago
7 0
The remainder is what can't fit in so you put to the side R then the number
UkoKoshka [18]3 years ago
7 0
You can use division problems by dividing then add
You might be interested in
I really need help with this section
Tpy6a [65]

Looks like you did most of it.

The next step would be setting them equal to 105, like the problem suggests.

5z+3x+7x=105

15x=105

x=7

Then we can plug back in to find the numbers.

5*7=35

3*7=21

7*7=49

35+21+49=105

The three numbers are 35, 21, 49.

Hope this helps.

頑張って!

5 0
3 years ago
Read 2 more answers
I definitely need help with this difficult math problem. -7x+y^3+7x^3+6x-3y^3-2x^3+3x
Mars2501 [29]
The answer is 2x-2y^3+5x^3
6 0
3 years ago
. The cost of 2 pizzas and 1 burger is ₹ 450. Write a linear equation for this situation and draw its graph.​
Akimi4 [234]

Answer:

The linear equation is;

Y = 450 - 2·X

Please find the included graph

Step-by-step explanation:

Whereby we have the following relation;

The cost of 1 pizza = X

The cost of 1 burger = Y

Hence;

450 = Y + 2·X

Which gives;

Y = 450 - 2·X

The linear equation for the situation is therefore as presented above

The graph of the linear equation can be plotted using the assumed data as follows;

Y,           X

1,           448

2,          446

3,         444

4,          442

5,          440

6,          438

7,          436

8,          434

9,          432

10,          430

11,          428

12,          426

13,          424

14,          422

15,          420

16,            418

8 0
2 years ago
Two ways to do a number line
lana66690 [7]
You can use a number line to add and subtract 
8 0
2 years ago
the length of a rectangular garden is 3 m greater than the width. The area of the garden is 70m squared. find the dimensions of
Lerok [7]
A = l x w

so you know that the length is 3m longer than the width, so you could use a formula to represent that

w = l + 3

you then substitute the second equation into the first to solve for l

70 = l x (l +3)
70 = l^2 + 3l

you could then rearrange the formula and solve for l using the quadratic formula 

0 = l^2 + 3l - 70

l = -3 +- (square root (3)^2 - 4(1)(70)) / 2(1)
l = -3 +- (square root 9 + 280) / 2
l = -3 +- (square root 289) / 2
l = -3 +- 17 / 2

then you solve for the two seperate roots

l = -3 + 17 /2
l = 14 / 2
l = 7

or 

l = -3 - 17 / 2
l = -20 / 2
l = -10

since a length cannot be negative, this root is not viable. therefore l = 7

to solve for w you would use

w = l + 3
w = 7 + 3
w = 10 

hope this helps! if you did not understand a step or concept please let me know!
4 0
3 years ago
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