Answer:
1. 11 A
2. 240 V
3. 8 Ω
4. 60 C
5. 14400 C
Explanation:
1. Determination of the current.
Voltage (V) = 110 V
Resistance (R) = 10 Ω
Current (I) =?
V = IR
110 = I × 10
Divide both side by 10
I = 110 / 10
I = 11 A
2. Determination of the voltage
Current (I) = 3 A
Resistance (R) = 80 Ω
Voltage (V) =?
V = IR
V = 3 × 80
V = 240 V
3. Determination of the resistance.
Current (I) = 0.5 A
Voltage (V) = 4 V
Resistance (R) =?
V = IR
4 = 0.5 × R
Divide both side by 0.5
R = 4 / 0.5
R = 8 Ω
4. Determination of the charge
Current (I) = 2 A
Time (t) = 30 s
Charge (Q) =?
Q = it
Q = 2 × 30
Q = 60 C
5. Determination of the charge.
We'll begin by converting 20 mins to seconds. This can be obtained as follow:
1 min = 60 s
Therefore,
20 mins = 20 × 60
20 mins = 1200 s
Finally, we shall determine the charge as follow:
Current (I) = 12 A
Time (t) = 1200 s
Charge (Q) =?
Q = it
Q = 12 × 1200
Q = 14400 C
Answer:
The centripetal force is 0.54 N.
Explanation:
mass, m = 0.56 kg
radius, r = 0.72 m
angular speed, w = 1.155 rad/s
The centripetal force is given by
Explanation:
Let us assume that the final resistance after stretching is 
. Since, the volume of rod does not change and the initial and final volume will be the same as follows.
V = 
It is given that, 
.
Therefore,
We know that relation between resistance and area is as follows.
R = 
= 
= 9 
= 9R
Thus, we can conclude that the resistance of the stretched wire is 9R.
The answer is Fuse, the Fuse has a low melting point
