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2 years ago

Given h ( x ) = − 3 x + 2 , solve for x when h ( x ) = − 4.

Mathematics

2 answers:

Helga [31]2 years ago

8 0

Answer:

2 is the answers for the question

Step-by-step explanation:

please mark me as brainlest

iris [78.8K]2 years ago

4 0

Answer:

h(2) = -4

Step-by-step explanation:

h(x)= -3x + 2

h(x) = -4

-3x + 2 = -4

-3x = -4 -2

-3x = -6

x = -6/-3

x = 2

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$f(x)=0+2x-2^2\dfrac{x^2}{2!}+2^3\cdot 2! \dfrac{x^3}{3!}+...+(-1)^{(n-1)}(n-1)!\cdot 2^n\dfrac{x^n}{n!}+...\\\\= 0 + 2x -2^2 \dfrac{x^2}{2!}+2^3\dfrac{x^3}{3!}+...+(-1)^{(n-1)}2^{n}\dfrac{x^n}{n}+...\\\\=\sum_{n=1}^{\infty}(-1)^{(n-1)}2^n\dfrac{x^n}{n}$

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